Archimedes' principle and its applications - class-XI

If the body displaces liquid whose weight is equal to the actual weight of body, the downward force weight will be balanced by the buoyant force and the body won't experience any net downward force in that case.

Answer is A.

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.
Hence, the given statement is true.

Answer is A.

The Archimedes principle, states that the buoyant force exerted on a body immersed in a fluid is equal to the weight of the fluid the body displaces. In other words, to calculate the buoyant force on an object we assume that the submersed part of the object is made of water and then calculate the weight of that water.
This principle is valid for any fluid not only liquids (such as water) but also gases (such as air).

Any substance sinks in a liquid of density of S when density of substance is greater than that of liquid i.e.

For a body to sink in water then density of body should be more than density of water or any fluid i.e. density of body > density of water.

Archimedes principle was an important work and has many application. It is used for designing submarines, ships etc. lactometer and hydrometer and also based on this principle and are used to check the purity of milk and density of liquids respectively.

Archimedes' principle states that the buoyant force applied to an object is equal to the weight of the fluid the object displaces.

Archimedes' Principle states that buoyant force acting on body upwards is equal in magnitude of the weight of liquid it displaces. Depending upon how much the body is immersed in liquid, and hence how much the weight of liquid is displaced, the buoyant force varies.

According to the Archimedes principle, the buoyant force acting on an object immersed in liquid is equal to the weight of liquid it displaces. Hence the buoyant force acting on the given object=$20kg\times 10m/s^2=200N$

Archimedes principle, states that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant force the magnitude of which is equal to the weight of the fluid displaced.

A balloon is filled with air at high pressure which leads to uprising of it because it experiences more buoyant force or we can say upthrust as they are same in this case.

Lactometer works on the Archimedes' Principle that a solid suspended in a fluid is buoyed by a force equal to the weight of the fluid displaced. If the milk sample is pure, then the lactometer floats on it and if it is adulterated or impure, then the lactometer sinks.

According to the Archimedes principle, the buoyant force of a submerged object is equal to the weight of the liquid displaced.

According to Archimedes principle , weight of body in water or liquid is equal to the weight of the liquid displaced by it.

wt. of man = 1000 N

According to Archemedies principle if any object is floating on a liquid the weight of the liquid displaced is equal to the weight of the object, when the block of ice melts the bullet ultimately sink in water and displaces the same volume of water as its own volume was, but when it was embedded in the ice it displaced move volume, therefore level of water will fall.

Given,

Loss in weight is dependent on volume of body.

Liquid displaced.
This is known as Archimedes principle.
Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

Answer is B

By Archimedes Principle, an object immersed(partially or fully) in a fluid experiences a loss in weight, which is given by the weight of the fluid displaced by the body.

Let the volume of cylinder be V

Same loss of weight implies equal buoyant forces on the object which is equal to weight of liquid displaced i.e. both the bodies have equal volumes.

$\dfrac { density\quad of\quad A }{ density\quad of\quad B } =\dfrac { density\quad of\quad immersed }{ Volume\quad of\quad B\quad immersed } =\dfrac { 1/2 }{ 2/3 } $

Buoyant force = weight of liquid displaced

Answer is C.

According to the laws of flotation, the more denser liquid will sink below and the less dense material will float.
In this case, the object R has the maximum density of $1200kg/{ m }^{ 3 }$.
Therefore, object R will sink when dipped in a bucket of water.

Given:
Mass of substance $= 70g$.
Volume of substance $= 35cm^3$
density of water $= 1gm^{-3}$
By using the formula,
Density $=\dfrac{Mass}{Volume}$
Density of sub stance $= \dfrac{70}{35}=2gm^{-3}$
since, the density of the substance is more than the density, the gravitational force acting on it will be stronger than the buoyant force of water acting it, it will sink and not float on the surface of water

Since , the ethanol is less denser than the water.Therefore, a piece of wood floating completely in water will sink in the ethanol.

As the density of liquid increases & so does the buoyant force on the submerged rod which will result in increase in upthrust.

When the density of the liquid is greater than that of object, then the weight of liquid displaced is greater than or equal to the weight of the object. This means that the buoyant force acting on the object is greater or equal to the weight of the object which makes the object to float in that liquid. 

Weight of the water displaced= weight of body + additional mass

Option (A) follows correct procedure as initially weight of the object is calculated in the air than it is immersed in liquid and its weight is measured in the liquid and then the diffrence between the two weights would be calculated  and than weight of liquid displaced by the body would be calculated and later the two diffrences would e compared.

Construction of a submarine is based on Archimedes' principle.

${V _f}^2-V _1^2=2as$

Since density of iron is more than that of wood, so weight of iron sphere will be more than upthrust due to water on it. But density of wood is less than that of iron so sphere of wood will float. 

The body will float if $\rho _{s}$ < $\rho _{L}$ and it will sink if $\rho _{s}$ > $\rho _{L}$
If the density of the substance is less than the density of the liquid, then the substance will float in liquid.
If the density of the substance is greater than the density of the liquid, then the substance will sink in liquid.

Using the equilibrium condition for floating bodies and the given ratios, the forces balance such that the upper block is fully supported by the buoyancy of the lower block and its own displacement.