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Phase Changes and Thermal Properties of Matter
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If, melting and boiling point of a liquid is $-{50}^{o}C$ and ${150}^{o}C$ respectively, and on the basis of this liquid a thermometer is formed with ${0}^{o}L$ representing the melting point as the minimum temperature on the scale and ${100}^{o}L$ representing the boiling point as the maximum temperature on the scale, find the melting and boiling point on this thermometer
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A
$0$ and ${100}^{o}L$ respectively
💡 Explanation:
By definition, the new thermometer scale is constructed by setting the melting point of the liquid (-50 deg C) as 0 deg L and the boiling point (150 deg C) as 100 deg L. Therefore, by construction, the melting and boiling points on this new scale are 0 and 100 deg L respectively.