🎴 Flashcard Mode
Capacitors - Series and Parallel Combinations
Card1 / 38
Mastered0
Review0
QuestionClick to flip
A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plate are $+\sigma$ and $-\sigma$ respectively. In the region between the plates the magnitude of electric field is:
AnswerClick to flip back
A
$\dfrac { \sigma }{ { \varepsilon } _{ 0 } } $
💡 Explanation:
The magnitude of the electric field due to a charged plate is given as:
$\vec E=\dfrac{\sigma}{2\varepsilon _0}$
The charge density on the upper plate is positive whereas on the lower plate it is negative.
Therefore, the electric field in the region between the two plates is the difference of the two fields.
It is given as:
$E _{net}=\dfrac{\sigma}{2\varepsilon _0}-\dfrac{-\sigma}{2\varepsilon _0}$
$E _{net}=\dfrac{\sigma}{\varepsilon _0}$