Questions
Heat of reaction at constant pressure is called
- Enthalpy.
- Entropy
- Free energy
- None of these
The relationship between enthalpy and internal energy change is
- $\,\Delta U = \Delta H + P\Delta V$
- $\,\Delta H = \Delta U + P\Delta V$
- $\,\Delta H = \Delta U - P\Delta V$
- $\,P\Delta V = \Delta U + \Delta H$
An athelete is given 100 g of glucose $(C _6H _{12}O _6)$ of energy equivalent to 1560 kJ. He utilises 50 percent of this gained energy in the event. In order to avoid storage of energy in the body, Determine the weight of water he would need to perspire. (The enthalpy of evaporation of water is 44 kJ/mole.)
- 319 gm
- 323 gm
- 342 gm
- 312
Enthalpy of the system is given as :
- $\displaystyle H+PV$
- $\displaystyle U+PV$
- $\displaystyle U-PV$
- $\displaystyle H-PV$
Under which of the following condition is the relation $\Delta H = \Delta U + P\Delta V$ valid for a closed system at
- constant pressure
- constant temperature
- constant temperature and pressure
- constant temperature, pressure and composition
In the hydrogenation of ethylene,$\Delta n$ is equal to:
- 1
- -2
- -1
- 2
For the reaction,
$C(s)+O _{2}(g)\rightarrow CO _{2}(g);$
$\Delta n$ value is __________.
- Zero
- +1
- -1
- unpredictable
What is abbreviated as '$H$'?
- Standard voltaic potential
- Entropy
- Enthalpy
- Reaction rate
Which of the following statements are correct?
- absolute value of enthalpy cannot be determined.
- absolute value of internal energy cannot be determined.
- absolute value of entropy can be determined.
- internal energy, enthalpy, and entropy are intensive properties.
Enthalpy of the system is given as
- $\,H + PV$
- $\,U + PV$
- $\,U - PV$
- $\,H - PV$
Which of the following reactions have same heat of reaction at constant $P$ and constant volume as well?
- $2NO(g)\longrightarrow N _2(g)+O _2(g)$
- $N _2(g)+3H _2(g)\longrightarrow 2NH _3(g)$
- $Co _3O _4(s)+4CO(g)\longrightarrow 3Co(s)+4CO _2(g)$
- $H _2(g)+Cl _2(g)\longrightarrow 2HCl(g)$
For which reaction will $\Delta H = \Delta U$?
- $H _2(g) + Br _2(g)\longrightarrow 2HBr(g)$
- $C(s) + 2H _2O(g)\longrightarrow 2H _2(g) + CO _2(g)$
- $4CO(g) + 2O _2(g)\longrightarrow 4CO _2(g)$
- $2PCl _5(g)\longrightarrow 2PCl _3(g) + 2Cl _2(g)$
In which of the following reactions, $\Delta H > \Delta U$?
- $H _2(g) + I _2(g)\rightarrow 2HI(g)$
- $PCl _5(g)\rightarrow PCl _3(g) + Cl _2(g)$
- $2H _2O _2(l)\rightarrow 2H _2O(l) + O _2(g)$
- $C(s) + O _2(g)\rightarrow CO _2(g)$
Enthalpy of the system is given as:
- $U + PV$
- $H = PV$
- $U - PV$
- $ H - V$
Match List I with List II and select the answer from the given codes.
List I List II
B. $N _2(g) + 3H _2(g)\longrightarrow 2NH _3(g)$ 2. $\Delta H = \Delta U$
C. $NH _4HS(s)\longrightarrow NH _3(g) + H _2S(g)$ 3. $\Delta H =\Delta U - 2RT$
D. $PCl _5(g)\longrightarrow PCl _3(g) + Cl _2(g)$ 4. $\Delta H = \Delta U + 2RT$
E. $2SO _2(g) + O _2(g)\longrightarrow 2SO _3(g)$ 5. $\Delta H = \Delta U - RT$
- $A-1, B-2, C-3, D-4, E-5$
- $A-5, B-2, C-3, D-4, E-1$
- $A-1, B-3, C-4, D-2, D-5$
- $A-2, B-3, C-4, D-1, E-5$
$H _2(g) + I _2(g)\longrightarrow 2HI(g)$
For this reaction, relate $\Delta H$ and $\Delta U$.
- $\Delta H$ =$\Delta U$
- $\Delta H$ > $\Delta U$
- $\Delta H$ < $\Delta U$
- None of these
Heat of reaction at constant pressure and heat of reaction at constant volume for the gaseous reaction $N _2 + 3H _2 \longrightarrow 2NH _3$ differ $(\Delta H- \Delta U)$ by the amount:
- $2RT$
- $-2RT$
- $3RT$
- $RT$
If $\Delta E$ is the heat of reaction for
${C} _{2}{H} _{5}OH\left(l\right) + 3{O} _{2}\left(g\right) \longrightarrow 2C{O} _{2}\left(g\right) + 3{H} _{2}O\left(l\right)$
at constant volume, the $\Delta H$ (heat of reaction at constant pressure), at constant temperature is:
- $\Delta H = \Delta E + RT$
- $\Delta H = \Delta E - RT$
- $\Delta H = \Delta E - 2RT$
- $\Delta H = \Delta E + 2RT$
For gaseous reactions, if $\Delta H$ is the change in enthalpy and $\Delta U$ that in internal energy, then
- $\Delta H$ is always greater than $\Delta U$
- $\Delta H$ is always less than $\Delta U$
- $\Delta H > \Delta U$ only if the number of mole of the products is less than that of the reactants.
- $\Delta U < \Delta H$ only if the number of mole of the reactants is less than that of the products.
At constant pressure:
- pdv=d(pv)
- dQ=du+d(pv)
- dQ=d(u+pv)
- all of the mentioned
For the combustion reaction at $298,K$
$2Ag(s) +1/2O _2(g)\longrightarrow 2Ag _2O(s)$ Which of the following alternative is correct?
- $\Delta H = \Delta U$
- $\Delta H > \Delta U$
- $\Delta H < \Delta U$
- $\Delta H and \Delta U$ bear no relation with each other
Hess's law is based on:
- Law of conservation of mass
- Law of conservation of energy
- Second law of thermodynamics
- None of the above
- True
- False
Select the correct option(s):
- $q=nC _{v}\mathrm{d} T$ is applicable to all substances during heating/cooling at constant 'v'.
- $q=nC _{v}\mathrm{d} T$ is applicable to ideal gas during heating/cooling at constant 'v'.
- $\mathrm{d} U=nC _{v}\mathrm{d} T$ is applicable for real gas at constant 'v'
- $\mathrm{d} U=nC _{v}\mathrm{d} T$ is applicable for ideal gas at constant 'v' only
Enthalpy change of a reaction will be equal to:
- $\Delta U + P\Delta V$
- $\Delta U + V\Delta P$
- $\Delta U + \Delta (PV)$
- $\Delta U + (\Delta n _{ g } )\Delta (PV)$
In an isothermal process:
- $q=0$ and $\Delta E=0$
- $q\neq 0$ and $\Delta E=0$
- $q=0$ and $\Delta E\neq 0$
- $q\neq 0$ and $\Delta E\neq 0$
Two reactions are given below:
- For (i) $\vartriangle$H < $\vartriangle$E and for (ii) $\vartriangle$H > $\vartriangle$E
- For (i) $\vartriangle$H > $\vartriangle$E and for (ii) $\vartriangle$H < $\vartriangle$E
- For both (i) and (ii) $\vartriangle$H > $\vartriangle$E
- For both (i) and (ii) $\vartriangle$H < $\vartriangle$E
Which of the following is abbreviated as $H$?
- Standard voltaic potential
- Entropy
- Enthalpy
- Reaction rate
- Gibbs free energy
- $H=h/m$
- $H=m/h$
- $H=m\times h$
- None of the mentioned
A mixture of 2 mole of carbon monoxide and one mole of oxygen in a closed vessel is ignited to get carbon dioxide. If $\Delta H$ is the enthalpy change and $\Delta U$ is the change in internal energy, then:
- $\Delta H >\Delta U$
- $\Delta H <\Delta U$
- $\Delta H =\Delta U$
- can't be predicted
Predict $\Delta H>\Delta U$ or $\Delta H<\Delta U$.
- a. $\Delta H = \Delta U$; b. $\Delta H>\Delta U$
- a. $\Delta H > \Delta U$; b. $\Delta H=\Delta U$
- a. $\Delta H >\Delta U$; b. $\Delta H<\Delta U$
- None of these
Water is boiled under a pressure of 1.0atm. When an electric current of 0.50A from a 12V supply is passed for 300 second through a resistance in thermal contact with it, it is found that 0.789g of water is vapourized. The molar internal energy change at boiling point (373.15K) is
- $\displaystyle =37.9kJ{ mol }^{ -1 }$
- $\displaystyle =27.5kJ{ mol }^{ -1 }$
- $\displaystyle =47.5kJ{ mol }^{ -1 }$
- $\displaystyle =17.5kJ{ mol }^{ -1 }$
A piston exerting a pressure of 1.0 atmosphere rests on the surface of water at $100^{\circ}C$. The pressure is reduced to smaller extent and as a result 10 g of water evaporates and absorbs 22.2 kJ of heat. The change in internal energy is:
- 18.24 kJ
- 20.477 kJ
- 22.05 kJ
- 23.923 kJ
Enthalpy is_________.
- Energy of reaction
- Tendency for loss of energy
- Tendency for randomness
- Use of energy in overcoming entropy
Statement I : An exothermic reaction has a positive $\displaystyle \Delta H$ value
Because
Statement II : Heat must be added to the reaction for the reaction to occur
- Statement 1 and Statement 2 are correct and Statement 2 is the correct explanation of Statement 1 .
- Both the Statement 1 and Statement 2 are correct and Statement 2 is not the correct explanation of Statement 1.
- Statement 1 is correct but Statement 2 is not correct.
- Statement 1 is not correct but Statement 2 is correct.
- Both the Statement 1 and Statement 2 are not correct.