Nuclear force - class-XII
Casual Mode - Take your time!
1 / 32
Correct
0
Incorrect
0
Score
0%
Multiple Choice
The binding energy per nucleon for $\mathrm { U } ^ { 238 }$ about 7.5Mev where as it is about 8.5 Mev for a nucleus having a mass half of Uranium. If $\mathrm { U } ^ { 238 }$ splits into two exact halves the energy released would be
- 6.4 Mev
- 119 Mev
- 238 Mev
- 476 Mev