Millionaire Mode

Standing waves in strings - class-XI

Question 1 of 27

A string is under tension so that its length is increased by $1/n$ times its original length. The ratio of fundamental frequency of longitudinal vibrations and transverse vibrations will be

  1. $1:n$
  2. ${n}^{2}:1$
  3. $\sqrt{n}:1$
  4. $n:n+1$

Prize Money

15₹7 Crores
14₹1 Crore
13₹50,00,000
12₹25,00,000
11₹12,50,000
10₹6,40,000
9₹3,20,000
8₹1,60,000
7₹80,000
6₹40,000
5₹20,000
4₹10,000
3₹5,000
2₹2,000
1₹1,000