Construction of triangle - class-VI
Learn triangle construction methods including SSS, SAS, ASA conditions, triangle inequality, and constructing right angled and isosceles triangles with given sides and angles
Questions
State true or false:
Ans: Yes
- True
- False
The steps for construction of $\triangle DEF$ with $DE = 4\ cm, EF=6.5\ cm$ and $DF = 8.6\ cm$ are given below in jumbled order:
1. Draw arcs of length $4\ cm$ from $4\ cm$ from $D$ and $6.5\ cm$ from $F$ and mark the intersection point as $E$.
2. Join $D-E$ and $F-E$.
3. Draw a line segment of length $DF = 8.6\ cm$.
The correct order of the steps is:
- $3-1-2$
- $1-2-3$
- $2-3-1$
- $2-1-3$
In $\triangle ABC$, $AB=5\ cm, BC= 6\ cm ,AC=4\ cm$. Identify the type of triangle.
- Right angled triangle
- Isosceles triangle
- Equilateral triangle
- Scalene triangle
The number of triangles with any three of the length 1, 4, 6 and 8 cms, as sides is
- 4
- 2
- 1
- 0
For construction of a $\triangle PQR$, where $\displaystyle QR=6\ cm, PR=10\ cm$ and $\angle Q=90^{\circ}$, its steps for construction is given below in jumbled form. Identify the third step from the following.
1. At point $ Q $, draw an angle of $ {90}^{\circ} $.
2. From $ R $ cut an arc of length $ PR = 10.0 \ cm $ using a compass.
3. Name the point of intersection of the arm of the angle $ {90}^{\circ} $ and the arc drawn in step 3, as $ P $.
4. Join $P $ to $ Q $ . $ PQR $ is the required triangle.
5. Draw the base side $ QR = 6\ cm $.
- $3$
- $4$
- $2$
- $5$
- $1$
The lengths of the sides of some triangles are given, which of them is not a right angled triangle?
- $5$ cm , $12$ cm, $13$ cm
- $7$ cm, $24$ cm, $25$ cm
- $5$ cm, $8$ cm, 1$0$ cm
- $3$ cm, $4$ cm, $5$ cm
Construct a right angled triangle $PQR$, in which $\angle Q = 90^\circ $, hypotenuse $PR=8,cm$ and $QR=4.5,cm$. Draw bisector of angle $PQR$ and let it meet $PR$ at point $T$ then $T$ is equidistant from$PQ$ and $QR$.
- True
- False
If $b=3, c=4, \angle B=\dfrac{\pi}{3}$, then the number of triangles that can be constructed is
- $0$
- $1$
- $3$
- $2$
- $5\ cm, 6\ cm , 4\ cm$
- $13\ cm , 12\ cm , 24\ cm$
- $2\ cm , 7\ cm , 9\ cm$
- $5.6\ cm , 6.5\ cm , 12\ cm$
The sides $A B , B C , C A$ of a triangle $A B C$ have $3,4$ and $5$ interior points respectively on them. The number of triangles that can be constructed using these points as vertices is
- $205$
- $210$
- $315$
- $216$
Mark the correct alternative of the following.
In which of the following cases can a right triangle ABC be constructed?
- $AB=5$cm, $BC=7$cm, $AC=10$cm
- $AB=7$cm, $BC=8$cm, $AC=12$cm
- $AB=8$cm, $BC=17$cm, $AC=15$cm
- None of these
Mark the correct alternative of the following.
In which of the following cases, a right triangle cannot be constructed?
- $12$cm, $5$cm, $13$cm
- $8$cm, $6$cm, $10$cm
- $5$cm, $9$cm, $11$cm
- None of these
Construct a $\triangle PQR$ in which $QR= 4.6\ cm., {\angle Q}={\angle R=50 ^{0}}$. Then the perimeter of the triangle is:
- $10.2\ cm$
- $13.2\ cm$
- $11.8\ cm$
- $12.4\ cm$
Construct a right angled $\triangle ABC$ with $\angle B = 90^\circ, BC = 5\ cm$ and $AC = 10\ cm$ and find the the length of side $AB$
- $6.2\ cm$
- $5\ cm$
- $8.7\ cm$
- $7.2\ cm$
- $30^\circ$
- $45^\circ$
- $60^\circ$
- $90^\circ$
Length of two sides of a $\triangle ABC$ is $AB=6\ cm$ and $BC=7\ cm$. Then, which of the following can represent the third side of the triangle ? Also, construct the triangle formed by these three sides.
- $8\ cm$
- $13\ cm$
- $14\ cm$
- $15\ cm$
The perimeter of a triangle is $45\ cm$. Length of the second side is twice the length of first side. The third side is $5$ more than the first side. Find the length of each sides and construct the triangle made by these three sides.
- $11,19,15$
- $10,20,15$
- $10,16,19$
- $13,15,17$
Construct a triangle $ABC$ in which $AB = 5 cm$ and $BC = 4.6 cm$ and $AC = 3.7 cm$
Steps for the construction is given in jumbled form.Choose the appropriate sequence for the above
1) With radius as $5\ cm$ from $C$, cut an arc.
2)They arcs will intersect at point $A$. Join $AB$ and $AC$. $ABC$ is the required triangle.
3)Draw a line segment $BC = 4\ cm.$
4)With radius as $3$ cm from $B$, cut the arc.
- $1,4,3,2$
- $4,3,2,1$
- $3,1,4,2$
- $4,1,3,2$
Construct an isosceles $\triangle XYZ,$ where $YZ=5$ units and $\angle XYZ=35^{o}$. Also, find the measure of $\angle YXZ$.
- $35^{o}$
- $70^{o}$
- $110^{o}$
- $140^{o}$
Construct an isosceles $\triangle ABC,$ where base $AB=7\ cm$ and $\angle ABC=50^{o}$. Also, find the measure of $\angle ACB$.
- $50^{0}$
- $80^{o}$
- $100^{o}$
- $120^{o}$
For construction of a $\triangle PQR$, where $\displaystyle QR=6\ cm, PR=10\ cm$ and $\angle Q=90^{\circ}$, its steps for construction is given below in jumbled form. Identify the fourth step from the following.
1. At point $ Q $, draw an angle of $ {90}^{\circ} $.
2. From $ R $ cut an arc of length $ PR = 10.0 \ cm $ using a compass .
3. Name the point of intersection of the arm of the angle $ {90}^{\circ} $ and the arc drawn in step 3, as $ P $.
4. Join $P $ to $ Q $ . $ PQR $ is the required triangle.
5. Draw the base side $ QR = 6\ cm $.
- $5$
- $1$
- $2$
- $3$
- $4$
State the following statement is True or False
In a right angle triangle $ABC$ such as $AC=5 cm ,BC=2 cm$ , $\angle B=90^o$
Then the length of $AB$ after construction is $7$cm
- True
- False
For construction of a $\triangle PQR$, where $\displaystyle QR=6\ cm, PR=10\ cm$ and $\angle Q=90^{\circ}$, its steps for construction is given below in jumbled form. Identify the second step from the following.
1. At point $ Q $, draw an angle of $ {90}^{\circ} $.
2. From $ R $ cut an arc of length $ PR = 10.0 \ cm $ using a compass.
3. Name the point of intersection of the arm of the angle $ {90}^{\circ} $ and the arc drawn in step 3, as $ P $.
4. Join $P $ to $ Q $ . $ PQR $ is the required triangle.
5. Draw the base side $ QR = 6\ cm $.
- $2$
- $1$
- $4$
- $5$
- $3$
For construction of a $\triangle PQR$, when $\displaystyle QR=6\ cm, PR=10\ cm$ and $\angle Q=90^{\circ}$, its steps for construction is given below in jumbled form. Identify the fifth step from the following.
1. At point $ Q $, draw an angle of $ {90}^{\circ} $.
2. From $ R $ cut an arc of length $ PR = 10.0 \ cm $ using a compass.
3. Name the point of intersection of the arm of the angle $ {90}^{\circ} $ and the arc drawn in step 3, as $ P $.
4. Join $P $ to $ Q $ . $ PQR $ is the required triangle.
5. Draw the base side $ QR = 6\ cm $.
- $2$
- $3$
- $1$
- $5$
- $4$
For construction of a $\triangle PQR$, where $\displaystyle QR=6\ cm, PR=10\ cm$ and $\angle Q=90^{\circ}$, its steps for construction is given below in jumbled form. Identify the first step from the following.
1. At point $ Q $, draw an angle of $ {90}^{\circ} $.
2. From $ R $ cut an arc of length $ PR = 10.0 \ cm $ using a compass .
3. Name the point of intersection of the arm of the angle $ {90}^{\circ} $ and the arc drawn in step 3, as $ P $.
4. Join $P $ to $ Q $ . $ PQR $ is the required triangle.
5. Draw the base side $ QR = 6\ cm $.
- $2$
- $1$
- $3$
- $5$
- $4$
Construct a triangle $ABC$, in which $AB = 5.5 cm, AC = 6.5 cm$ and $\angle BAC = 70^{\circ}$.
Steps for its construction is given in a jumbled form.Identify its correct sequence.
1) At $A$, construct a line segment $AE$, sufficiently large, such that $\angle BAC$ at $70^\circ$, use protractor to measure $70^\circ$
2) Draw a line segment which is sufficiently long using ruler.
3) With $A$ as centre and radius $6.5cm$, draw the line cutting $AE$ at C, join $BC$, then $ABC$ is the required triangle.
4) Locate points $A$ and $B$ on it such that $AB = 5.5cm$.
- $2,4,1,3$
- $2,1,4,3$
- $1,2,4,3$
- $4,2,1,3$
Which of the following steps is INCORRECT, while constructing $\triangle$LMN, right angled at M, given that LN = 5 cm and MN = 3 cm?
Step 1. Draw MN of length 3 cm.
Step 2. At M, draw MX $\perp$ MN. (L should be some where on this perpendicular).
Step 3. With N as centre, draw an arc of radius 5 cm. (L must be on this arc, since it is at a distance of 5 cm from N).
Step 4. L has to be on the perpendicular line MX as well as on the arc drawn with centre N. Therefore, L is the meeting point of these two and $\triangle$LMN is obtained.
- Only Step 4
- Both Step 2 and Step 3
- Only Step 2
- None of these