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Introduction to factorization - class-X

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QuestionClick to flip

Factorise ${\left( {3 - 4y - 7{y^2}} \right)^2} - {\left( {4y + 1} \right)^2}$

AnswerClick to flip back

$\left( {4 - 7{y^2}} \right)\left( {2 - 8y - 7{y^2}} \right)$

💡 Explanation:

We have,

${\left( {3 - 4y - 7{y^2}} \right)^2} - {\left( {4y + 1} \right)^2}$

We know that

$a^2-b^2=(a+b)(a-b)$

Therefore,

$\Rightarrow (3 - 4y - 7y^2+4y + 1)(3-4y-7y^2-4y-1) $

$\Rightarrow (4 - 7y^2)(2-8y-7y^2) $

Hence, this is the answer.