Questions
Which of the following can be calculated from Born-Haber cycle for $Al _2O _3$?
- Lattice energy of $Al _2O _3$
- Electron affinity of O-atom
- Ionisation energy of Al
- All of these
In the series $Sc(Z=21)$ to $Zn(Z=30)$, the enthalpy of atomisation of which element is least?
- Sc
- Mn
- Cu
- Zn
The lattice energy of CsI(s) is −604 KJ/mol, and the enthalpy of solution is 33 KJ/mol. How would you calculate the enthalpy of hydration (KJ) of 0.65 moles of CSI? Enter a numeric answer only, do not include units in your answer?
- $738 KJ $
- $ 10 KJ $
- $-371 kj$
- $-822 KJ$
Consider the following reaction,
$2A + B \rightarrow C + 2D$, $\Delta H _{1} = 10$
$A + 2C \rightarrow 2D + B$, $\Delta H _{2} = -5$ What is $\Delta H$ of reaction $A + 2B \rightarrow 3C$?
- $-5$
- $+5$
- $+10$
- $+15$
Determine ${ \Delta }{ U }^{ o }$ at $300K$ for the following reaction using the listed enthalpies of reaction:
$4CO(g)+8{ H } _{ 2 }(g)\longrightarrow 3{ CH } _{ 4 }(g)+{ CO } _{ 2 }(g)+2{ H } _{ 2 }O(l)$
$C _{(graphite)}+1/2{ O } _{ 2 }(g)\longrightarrow CO(g);\quad \Delta { { H } _{ 1 } }^{ o }=-110.5kJ$
$CO(g)+1/2{ O } _{ 2 }(g)\longrightarrow { CO } _{ 2 }(g);\quad \Delta { { H } _{ 2 } }^{ o }=-282.9kJ$
${ H } _{ 2 }(g)+1/2{ O } _{ 2 }(g)\longrightarrow { H } _{ 2 }O(l);\quad \Delta { { H } _{ 3 } }^{ o }=-285.8kJ$
$C _{(graphite)}+2{ H } _{ 2 }(g)\longrightarrow { CH } _{ 4 }(g);\quad \Delta { { H } _{ 4 } }^{ o }=-74.8kJ$
- $653.5\ kJ$
- $-686.2\ kJ$
- $-747.4\ kJ$
- None of these
The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v : ${ \Delta H } _{ atomisation }$ K = 90 kJ/mol
w : ${ \Delta H } _{ ionisation }$ K = 418 kJ/mol
x : ${ \Delta H } _{ dissociation }$ H = 436 kJ/mol
y : ${ \Delta H } _{ electron affinity }$ H = 78 kJ/mol
z : ${ \Delta H } _{ lattice }$ KH = 710 kJ/mol
${ \Delta H } _{ i }$ of K is ${ \Delta H } _{ i }$ = $w/2$.
If true enter 1, else enter 0.
- 0
- 1
- 2
- 3
v : ${ \Delta H } _{ atomisation }$ $K = 90 kJ/mol$
w : ${ \Delta H } _{ ionisation }$ $K = 418 kJ/mol$
x : ${ \Delta H } _{ dissociation }$ $H = 436 kJ/mol$
y : ${ \Delta H } _{ electron affinity }$ $H = 78 kJ/mol$
z : ${ \Delta H } _{ lattice }$ $KH = 710 kJ/mol$
- $39$
- $40$
- $41$
- None of these
The Born Haber cycle below represents the energy changes occurring at 298K when $KH$ is formed from its elements
v : ${ \Delta H } _{ atomisation }$ $K = 90 kJ/mol$
w : ${ \Delta H } _{ ionisation }$ $K = 418 kJ/mol$
x : ${ \Delta H } _{ dissociation }$ $H = 436 kJ/mol$
y : ${ \Delta H } _{ electron affinity }$ $H = 78 kJ/mol$
z : ${ \Delta H } _{ lattice }$ $KH = 710 kJ/mol$
- 124 kJ/mol
- -124 kJ/mol
- 124 J/mol
- None of these
The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v : ${ \Delta H } _{ atomisation }$ K = 90 kJ/mol
w : ${ \Delta H } _{ ionisation }$ K = 418 kJ/mol
x : ${ \Delta H } _{ dissociation }$ H = 436 kJ/mol
y : ${ \Delta H } _{ electron affinity }$ H = 78 kJ/mol
z : ${ \Delta H } _{ lattice }$ KH = 710 kJ/mol
${ \Delta H } _{ electron affinity }$ of H is ${ \Delta H } _{ electron affinity }$ is __.
I
- $y$
- $y/2$
- $2y$
- $y/3$
The energy change for the alternating reaction that yields chlorine sodium $(Cl^{+}Na^{-})$ will be:
$2Na(s)\, +\, Cl _2(g)\,\rightarrow\, 2Cl^{+}Na^{-}(s)$
Given that:
Lattice energy of $NaCl\,=\,-787\, kJ\,mol^{-1}$
Electron affinity of $Na\,=\,-52.9\, kJ\, mol^{-1}$
Ionisation energy of $Cl\, =\, +\,1251\, kJ\, mol^{-1}$
BE of $Cl _2\,=\,244\, kJ\, mol^{-1}$
Heat of sublimation of $Na(s)\, =\,107.3\, kJ\, mol^{-1}$
$\Delta H _f(NaCl)\, =\,-411\, kJ\, mol^{-1}$.
- +640 kJ
- +1280 kJ
- -410 kJ
- +410 kJ
The lattice energy of NaCl(s) using the following data will be:
heat of sublimation of $Na(s)\,=\,S$
$(IE) _1$ of $Na\,(g)\,=\,I$
bond dissociation energy of $Cl _2\,(g)\,=\,D$
electron affinity of $Cl\,(g)\,=\,-E$
heat of formation of $NaCl(s)\,=\,-Q$- Lattice energy $-U\, =\, S\, +\, I\, +\,\displaystyle \frac{D}{2}\, -\, E\, -\,Q$
- Lattice energy $-U\, =\, S\, -\, I\, +\,\displaystyle \frac{D}{2}\, -\, E\, -\,Q$
- Lattice energy $-U\, =\, S\, +\, I\, +\,\displaystyle \frac{D}{2}\, +\, E\, -\,Q$
- Lattice energy $-U\, =\, S\, -\, I\, -\,\displaystyle \frac{D}{2}\, +\, E\, +\,Q$
Use the following data to calculate second electron ainity of oxygen, i.e., for the process
$O^{-}(g) + e^{-}(g) \rightarrow O^{2-}(g)$
Is the $O^{2-}$ ion stable in the gas phase?.Why is it stable in solid MgO?
Heat of sublimation of $Mg(s) = + 147.7 kJ mol^{-1}$
Ionisation energy of Mg(g) to form
$Mg^{2+}(g) = + 2189.0 kJ mol^{-1}$
Bond dissociation energy for $O _2 = + 498.4 kJmol^{-1}$
First electron affinity of $O(g) = - 141.0 kJ mol^{-1}$
Heat formation of $MgO(s) = -601.7 kJ mol^{-1}$
Lattice energy of $MgO = -3791.0 kJ mol^{-1}$
- 601.7
- 744.4
- 1346.1
- 147.7
Select correct statement.
- Both lattice energy and hydration energies decrease with ionic size.
- Lattice energy can be calculated using Born-Haber cycle.
- If the anion is larger compared to the cation, the lattice energy will remain almost constant within a particular group.
- All the above are correct statements.
Caesium chloride is formed according to the following equation:
- $-618.7\ kJ{mol}^{-1}$
- $+618.7\ kJ{mol}^{-1}$
- $1315.2\ kJ{mol}^{-1}$
- None of these
The ionization potential of ithium is 520 KJ/ mole .The energy required to convert 70 mg of lithum atoms in gaseous state into $Li^{+}$ ions is ______________.
- 52 KJ
- 5.2 KJ
- 520 KJ
- 52 J
The atoms of hydrogen combine to form a molecule of hydrogen gas, the energy of the $H _2$ molecule is:
- Greater than that of seperate atoms
- Equal to that of seperate atoms
- Lower than that of seperate atoms
- Some times lower and some times higher
Which of the following bonds has the highest bond energy?
- Si-Si
- Si=Si
- Si-O
- Si=O
Born Haber cycle is used to determine:
- electron affinity
- lattice energy
- crystal energy
- all the above
Choose the correct statement about the process (I) and (II).
- In $(I)$ energy released. $(II)$ energy absorbed
- In both $(I)$ and $(II)$ energy is absorbed
- In both $(I)$ and $(II)$ energy is released
- In $(I)$ energy absorbed, $(II)$ energy released
For the maximum ionic character during bond formation ,_________ on cation and a __________ anion are required.
- low charge, high charge
- low charge, low charge
- high charge , no charge
- none of these
The standard formation reaction for aluminium oxide is $4Al(s) + 6O(g)\rightarrow 2Al _2O _3(s)$. This statement is false because:
- aluminium is not in its standard state
- the reaction should be written for one mole of Al
- The reaction is prevented by a thin film of $Al _2O _3$ formed on the surface of Al
- none of these
Standard enthalpy of formation $(\Delta H _f)$ of which of the following is zero at $25^0C$ ?
- White phosphorous
- Red phosphorous
- Red lead $(Pb _3O _4)$
- $H^+(g)$
The heat change for the reaction: $C(s) + S(s)\rightarrow CS _2(l)$, known as:
- heat of transition
- heat of fusion
- heat of vapourisation
- heat of formation
Enthalpy of a solution of $ CsBr(s)$ is $10\ kJ/mol$.If the enthalpies of hydration of $Cs^+(g)$ and $Br(g)$ are 475 and 655 kJ.mol, what should be the lattice energy of $CsBr(s)$ in $kJ/mol$:
- $1120$
- $1130$
- $1140$
- $1150$