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Series Summation Methods - Class XI
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If y= -1 then the value of
$\displaystyle 1+\frac{1}{y}+\frac{1}{y^{2}}+\frac{1}{y^{3}}+\frac{1}{y^{4}}+\frac{1}{y^{5}}$ is
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A
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💡 Explanation:
$1+\frac{1}{y}+\frac{1}{y^{2}}+\frac{1}{y^{3}}+\frac{1}{y^{4}}+\frac{1}{y^{5}}$
Put the value y=-1
Then $1+\frac{1}{-1}+\frac{1}{(-1)^{2}}+\frac{1}{(-1)^{3}}+\frac{1}{(-1)^{4}}+\frac{1}{(-1)^{5}}= 1-1+1-1+1-1= 3-3=0$