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Meter bridge - class-X
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In a meter bridge experiment, the ratio of the left gap resistance to right gap resistance is $2 : 3$, the balance point from left is?
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A
$40$cm
💡 Explanation:
Let $X$ is the left gap resistance and $R$ is the right gap resistance
$l _1$ be the balance point from left
From meter Bridge principle:-
$\implies \dfrac XR= \dfrac{l _1}{100-l _1}=\dfrac23$
$\implies 200-2l _1= 3l _1 \implies 200=5l _1$
$l _1= 40\ cm $
Hence option $(C)$ is correct