Fundamental theorem of calculus - class-XII
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Multiple Choice
The value of $\displaystyle \int _0^1\tan^{-1}\left (\frac {2x-1}{1+x-x^2}\right )dx$ is
- $1$
- $0$
- $-1$
- $\dfrac {\pi}{4}$
Casual Mode - Take your time!
The value of $\displaystyle \int _0^1\tan^{-1}\left (\frac {2x-1}{1+x-x^2}\right )dx$ is