Questions
A square field is 40m long. The perimeter of the square field is (in cm)
- $14000 \, cm$
- $16000 \, cm$
- $12000 \, cm$
- $8000 \, cm$
By converting the $0.0287m^2$ into the $cm^2$, the answer will be
- $28.7 \, cm^2$
- $2870 \, cm^2$
- $287 \, cm^2$
- None of these
$10^{-5} , m^2=? , hectare$
- $1$
- $10$
- $10^{-2}$
- $10^{-1}$
A rectangular field is 40m long and 30m wide. perimeter of rectangular field is
- $120$m
- $130$m
- $140$m
- $150$m
If $1 , m^2$ of a certain plot in a certain area costs Rs. $1500,$ how much does $1$ hectare cost?
- $15 \times 10^5$
- $15 \times 10^6$
- $15 \times 10^7$
- $15 \times 10^4$
By converting the 80.2km into the hectare, the answer will be
- 0.08020ha
- 8020ha
- 802ha
- 0.802ha
By converting the 4.8mm into the cm, the answer will be
- 0.048cm
- 0.48cm
- 48cm
- 480cm
$500.2867 m^2= , ? hectare$
- $5002.867$
- $5002867$
- $500.2867$
- $0.05002867$
$10^{-10} , cm^2=? , hectare$
- $10^{-28}$
- $10^{-8}$
- $10^{-18}$
- $10^{18}$
By converting the $4.8mm^{2}$ into the $m^2,$ the answer will be
- $4.8 \times 10^{-7} m^2$
- $4.8 \times 10^{-6} m^2$
- $4.8 \times 10^{-8} m^2 $
- $4.8 \times 10^{-5}m^2$
Consider the railway platform which is in square shape having side length $2\ km$. Then area of the platform is $4$ ____.
- $m$
- $km$
- $km^{2}$
- $m^{2}$
The area of a square field is $30\dfrac {1}{4}m^2$. Calculate the length of the side of the square.
- $5\dfrac {1}{3}m$
- $5\dfrac {1}{2}m$
- $5\dfrac {2}{5}m$
- $5\dfrac {1}{4}m$
The area of a square field is $80\dfrac {244}{729}$ square metres. Find the length of each sides field.
- $8\dfrac {25}{27}m$
- $8\dfrac {24}{27}m$
- $8\dfrac {26}{27}m$
- $8\dfrac {22}{27}m$
The area of a square field is $325\ m^2$. Find the approximate length of one side of the field. (upto 2 places of decimals) (in $m^2$)
- $19.03$
- $18.02$
- $18.03$
- $17.03$
The area of a square playground is $256.6404$ square metres. Find the length of one side of the playground.
- $16.04$ metres
- $16.02$ metres
- $16.06$ metres
- $16.08$ metres
By converting the $5.6 m^2$ into the $cm^2$, the answer will be
- $0.0056cm^2$
- $5600cm^2$
- $56000cm^2$
- $560cm^2$
Which would be weight closest to 800 kg?
- Feather
- Ball
- Cow
- None of these
Subtract $2\ \text{kg}\ 54\ \text{g}$ from $12\ \text{kg}\ 530\ \text{g}$.
- $10\ \text{kg}\ 476\ \text{g}$
- $104\ \text{kg}\ 76\ \text{g}$
- $1\ \text{kg}\ 476\ \text{g}$
- $1047\ \text{kg}\ 6\ \text{g}$
Subtract $21\ kg\ 370\ g$ from $37\ kg\ 675\ g$ without conversion into gram.
- $15\ kg\ 305\ g$
- $15\ kg\ 470\ g$
- $16\ kg\ 305\ g$
- $16\ kg\ 300\ g$
A truck was loaded with $482\ kg\ 100\ g$ of pumpkins and $307\ kg\ 432\ g$ of watermelons. Find the total weight carried by the truck.
- $78\ kg\ 953\ g$
- $789\ kg\ 532\ g$
- $89\ kg\ 532\ g$
- $780\ kg\ 432\ g$
A shopkeeper purchased $392\ kg\ 500\ g$ of orange. Later on, he found that $56\ kg\ 460\ g$ of oranges were rotten. Find the quantity of oranges in good condition.
- $330\ kg\ 400\ g$
- $336\ kg\ 4\ g$
- $336\ kg\ 40\ g$
- $33.6\ kg\ 40\ g$
Add $95\ kg\ 45\ g$ and $45\ kg\ 300\ g$.
- $14\ kg\ 34\ g$
- $140\ kg\ 300\ g$
- $14\ kg\ 345\ g$
- $140\ kg\ 345\ g$
If Raina weighs $54\ kg\ 43\ g$ and Rohit weighs $60\ kg\ 760\ g$. Then, the sum of weights of Raina and Rohit is :
- $114\ kg\ 803\ g$
- $115\ kg\ 19\ g$
- $110\ kg\ 703\ g$
- $104\ kg\ 803\ g$
Average weight of $25$ persons is increased by $1$ kg when one man weighing $60$ kg is replaced by a new person. Weight of new person is
- $50$ kg
- $61$ kg
- $86$ kg
- $85$ kg
If $A$ weighs $43\ kg\ 234\ g$ and $B$ weighs $56\ kg\ 450\ g$. Then the difference between the weights of $A$ and $B$ is :
- $12\ kg\ 811\ g$
- $13\ kg\ 216\ g$
- $13\ kg\ 306\ g$
- $10\ kg\ 216\ g$
Add $17\ kg,13\ kg\ 940\ g$ and $15\ kg\ 65\ g$.
- $40\ kg\ 65\ g$
- $4\ kg\ 650\ g$
- $46\ kg\ 50\ g$
- $46\ kg\ 5\ g$