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Angle sum property of a triangle - class-VIII
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In $\triangle ABC$, if $b\cos A=a\cos B$ then the triangle is
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A
isosceless
💡 Explanation:
Given
In $\triangle ABC,b\cos A=a\cos B$
$2{R}\sin B\cos A=2{R}\sin A \cos B$
$\sin (B-A)=0\implies B=A$