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Kirchoff's Law of Thermal Radiation
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If the emissive and absorptive powers of a body are $E$ and $A $ respectively at temperature $T$ then emissive power of a black body will be
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A
$E/A$
💡 Explanation:
If Emissive power =$ E$
Absorptive power = $A$
The emissive power of a black body is the emissive power for unit absorptive power(per unit absorptive power) (Black body absorbs all radiations) = $\dfrac{E}{A}$