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Comparing decimals - class-V
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Of the numbers 0.16, $\displaystyle \sqrt{0.16}$, $\displaystyle (0.16)^{2}$ and $\displaystyle 0.1\overline{6}$ the least number is
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A
$\displaystyle (0.16)^{2}$
💡 Explanation:
0.16 = 0.16
$\displaystyle \sqrt{0.16}=0.4 $ $\displaystyle \Rightarrow 0.0256=\left ( 0.16 \right )^{2}$
$\displaystyle \left ( 0.16 \right )^{2}=0.0256 $ $\displaystyle \Rightarrow 0.0256=\left ( 0.16 \right )^{2}$
$\displaystyle 0.\overline{16}=0.1666....$ $\displaystyle \Rightarrow 0.0256=\left ( 0.16 \right )^{2}$
is the least