Measurement of Distances: Parallax Method and Precision Instruments
Quiz on measuring distances using parallax method for astronomical distances and precision instruments like spherometer for small-scale measurements
Questions
Which one of the following methods is used to measure distance of a planet or a star from the earth?
- Echo method
- Parallax method
- Triangulation method
- None of these
'The parallax angle in radians is: $\theta = \left( 1 + \frac { 54 } { 60 } \right) \times \frac { \pi } { 180 } = 0.03316 \mathrm { rad }$
Hence, the distance between moon and earth:
- $\dfrac { \text { Diameter of Earth } } { \theta }$
- $\dfrac { 1.276 \times 10 ^ { 7 } m } { 0.03316 }$
- $3.84 \times 10 ^ { 8 } m$
- nnone of these
Which of the following instrument can be used to determine the radius of curvature of a spherical surface?
- Spherometer
- Vernier callipers
- Screw gauge
- Simple pendulum
Parallax method is suitable for the measurement of:
- ball
- planet
- vehicle
- distance between cities
Which of the following is the best method to measure microscopic distances?
- Optical microscope
- Meter scale
- Screw gauge
- Diffraction pattern
What is the approximation made in the parallax method?
- All distances measured between two points on earth is zero.
- All distances measured between two points on earth is constant.
- Distance between a point on the earth and the planet is very large as compared to the distance between two points on earth's surface.
- No approximation is made.
Two stars $S _1$ and $S _2$ are located at distances $d _1$ and $d _2$ respectively. Also if $d _1>d _2$ then which of the following statements is true?
- The parallax of $S _1$ and $S _2$ are same.
- The parallax of $S _1$ is twice as that of $S _2$.
- The parallax of $S _1$ is greater than parallax of $S _2$
- The parallax of $S _2$ is greater than parallax of $S _1$
Parallax is the apparent displacement of an object because of:
- change in observer's point of view
- change in object's position
- changes both in observers point of view and object's position
- consistency in observer's point of view
Parallax method is useful
- <span>for measuring speed of the light.</span>
- <span>for measuring distances of star.</span>
- for finding the intensity of the light.
- None of the above.
To minimise parallax error, the observer should place the object :
- as near to the scale of the ruler as possible and the eye must be directly above the scale
- as far to the scale of the ruler as possible and the eye must be directly above the scale
- as near to the scale of the ruler as possible and the eye must be to the right of the scale
- as near to the scale of the ruler as possible and the eye must be to the left of the scale
The effect of parallax is used to measure:
- distances to nearby objects
- distances to nearby stars
- nearness of atoms in substances
- the object and image distance in optical experiments
A star has a parallax angle p of 0.723 arcseconds. What is the distance of the star?
- 1.38 parsecs
- 2.38 parsecs
- 3.38 parsecs
- 4.38 parsecs
Error due to eye vision is termed as :
- climax error
- sight error
- parallax error
- visional error
A star's distance ($d$) and its parallax angle ($p$) are related to each other as:
- $d=\dfrac{1}{p}$
- $d=\dfrac{1}{p^2}$
- $p=\dfrac{1}{d^2}$
- none of these
Parallax method is based on which of the following principle?
- Disparity
- Lutz Kelker bias
- Trilateration
- Triangulation
Parallax angles _______ $0.01/ arcsec$ are very difficult to measure from Earth.
- more than
- less than
- equal to
- greater than or equal to
A student measure the height h of a convex mirror using spherometer. The legs of the spherometer are 4 cm apart and there are 10 divisions per cm on its linear scale and circular scale has 50 divisions. The student takes 2 as linear scale division and 40 as circular scale division. What is the radius of curvature of the convex mirror ?
- $9.06 cm$
- $20.66 cm$
- $5.66 cm$
- $9.66 cm$
A spherometer has 10 threads per cm and its circular scale has 50 divisions. The least count of the instrument is
- $0.01 cm$
- $0.02 cm$
- $0.002 cm$
- $0.2 cm$
If a star is $5.2\times 10^{16}\ m$ away. What is the parallax angle in degrees?
- $1.67 \times 10^{-4}$ degrees
- $1.67 \times 10^{-5}$ degrees
- $0.67 \times 10^{-4}$ degrees
- $2.3 \times 10^{-4}$ degrees
A star is $1.45\ parsec$ light years away. How much parallax would this star show when viewed from two locations of the earth six months apart in its orbit around the sun?
- $2\ Parsec$
- $0.725\ Parsec$
- $1.45\ Parsec$
- $2.9\ Parsec$