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Negative Exponents and Indices - Class VIII

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$5^{-2}$ can also be expressed as

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A
$\dfrac{1}{25}$
💡 Explanation:
$5^{-2}=5^{-1*2}$

$=(5^2)^{-1}$                       $\because  (a)^{mn}=(a^m)^n$

$=\dfrac{1}{5^2}$                              $\because a^{-n}=\dfrac{1}{a^n}$

$=\dfrac{1}{25}$
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