Questions
Which of the following statement is incorrect about electrochemical cell?
- Electrons are released at anode
- Chemical energy is converted into electrical energy
- Salt bridge maintains the electrical neutrality of the electrilytes
- Cell can work indefinitely
The following electrochemical cell is taken $Cu| Cu^{2+}(aq)|| Ag^{+}(aq))| Ag$ and has emf $E _{r}>0$ by which of the following actions $E _{1}$ increases?
- Adding $NH _{3}$ to the cathodic chamber
- Adding $HCl$ to the cathodic chamber
- Adding $AgNO _{3}$ to the anodic chamber
- Adding $NH _{3}$ to the anodic chamber
Find out ${E} _{cell}$ of following electrochemical cell (${E} _{{Br} _{2}/{Br}^{-}}=1.09V$)
$Pt(s)\mid {Br} _{2}(l)\mid{Br}^{-}(0.01M)\mid\mid{H}^{+}(0.01M)\mid{H} _{2}(g)(1bar)\mid Pt(s)$
- $-1.32V$
- $+1.09V$
- $-2.15V$
- $-1.92V$
The following electrochemical cell has been set up: $Pt(s)|Fe^{3+}, Fe^{2+}(a=1)||Ce^{4+}, Ce^{3+}(a=1)|Pt(s); E^{\circ}(Fe^{3+}|Fe^{2+})= 0.77V$; $E^{\circ}(Ce^{4+}|Ce^{3+})= 1.61V$. If an ammeter is connected between the two platinum electrodes, predict the direction of flow of current. Will the current increase or decrease with time?
- Ce electrode to Fe electrode, decrease
- Ce electrode to Fe electrode, increase
- Fe electrode to Ce electrode, decrease
- Fe electrode to Ce electrode, increase
After some time, the voltage of an electrochemical cell becomes zero. This is because ____________________.
- their electrode potential becomes zero.
- their reduction potential become equal but have opposite sign
- their reduction potential become equal and have the same sign.
- the ions of the electrolyte in the salt bridge stop moving.
Which one of the following statements is incorrect regarding an electrochemical cell?
- The electrode on which oxidation takes place is called anode.
- Anode is the negative pole.
- The direction of the current is same as that of the direction of flow of electrons.
- The flow of current is partly due to flow of electrons and partly due to flow of ions.
The first electro-chemical was invented by:
- Luigi Galvani.
- Alessandro Volta.
- Deniel.
- Lechanche
Statement $1$: In an electrolytic cell, the anode becomes positive and the cathode becomes negative.
Statement $2$: Anions migrate to the anode and cations migrate to the cathode.
- Statement $1$ and Statement $2$ are correct and Statement 2 is the correct explanation of Statement $1$.
- Both the Statement $1$ and Statement $2$ are correct, but Statement $2$ is NOT the correct explanation of Statement $1$.
- Statement $1$ is correct, but Statement $2$ is not correct.
- Statement $1$ is not correct, but Statement $2$ is correct.
The apparatus in which electrical energy is converted into chemical energy is known as:
- voltameter
- coulometer
- both (A) and (B)
- none of these
Consider a spontaneous electrochemical cell containing $Cd, Cd^{2+}, Ag^{+}$, and $Ag$.
The reduction potential of $Cd$ is $-0.403\ V$ and $Ag$ is $0.799\ V$.
- $Ag^{+} + Cd \rightarrow Cd^{2+} + Ag; 1.19\ V$
- $2Ag^{+} + Cd \rightarrow Cd^{2+} + 2Ag; 1.20\ V$
- $Ag^{+} + Cd \rightarrow Cd^{2+} + Ag^{+}; 0.40\ V$
- $2Ag^{+} + Cd \rightarrow Cd^{2+} + 2Ag; 2,30\ V$
Which of the following is true of an electrolytic cell?
- An electric current causes an otherwise non-spontaneous chemical reaction to occur.
- Reduction occurs at the anode
- A spontaneous electrochemical reaction produces an electric current
- The electrode to which the electrons flow is where oxidation occurs
- None of the above
The chemical change in an electrolytic cell is non-spontaneous.
- True
- False
What is a voltaic cell?
- A cell in which a spontaneous redox reaction produces electricity.
- A cell in which an oxidation reaction produces electricity.
- A cell that produces voltage.
- A cell full of volts.
- Any cell that undergoes a spontaneous reaction.
The value of equilibrium constant for a feasible cell reaction is:
- $< 1$
- $= 1$
- $> 1$
- zero
An electrochemical cell consists of?
- A cathode, anode, electrolyte, wire and two compartments.
- Cathode, anode, and wire
- Two compartments that conduct electricity.
- A positive and negative side.
- A cathode and an anode.
Consider the reaction;
$Cl _2(g)+2Br^-(aq)\rightarrow 2Cl^-(aq)+Br _2$
The emf of the cell when
$[Cl^-]=[Br _2]=[Br]=0.01 M$ and $Cl _2$ gas at 1 atm pressure will be: ($E^0$ for the above reaction is = 0.29 volt)
- 0.54 volt
- 0.35 volt
- 0.24 volt
- -0.29 volt
In an electrochemical cell, anode and cathode are__________.
- Positively and negatively charges ions
- Positively and negatively charges electrodes
- Negatively and positively charged electrodes
- Negatively and positively charged ions
Electrochemical cells are also called:
- electrolytic cells
- galvanic cells
- fuel cells
- voltaic cells
Foe the electrochemical cell:
$Zn\left( s \right) |{ Zn }^{ 2+ }\left( aq \right) \parallel { Cl }^{ - }\left( aq \right) |{ Cl } _{ 2 }\left( g \right) |Pt\left( s \right) $
Given : ${ E } _{ { Zn }^{ 2+ }/Zn }^{ o }=-0.76\ Volt$
${ E } _{ { Cl }^{ - }/{ Cl } _{ 2 }\left( g \right) }^{ o }=-1.36\ Volt$
From these data one can deduce that:
- $Zn + Cl _{2} \rightleftharpoons Zn^{2+} + 2Cl^{-}$ is a non-spontaneous reaction at standard conditions.
- $Zn^{2+} + 2Cl^{-} \rightleftharpoons Cl _{2} + Zn$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 2.12\ volt.$
- $Zn + Cl _{2} \longrightarrow Zn^{2+} + 2 Cl^{-}$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 2.12\ volt.$
- $Zn + Cl _{2} \longrightarrow Zn^{2+} + 2 Cl^{-}$ is a spontaneous reaction at standard conditions with ${ E } _{ cell }^{ o } = 0.60\ volt.$
In an electrolytic cell:
- anode is positively charged
- cathode is negatively charged
- oxidation takes place at anode
- reduction takes place at cathode
The electrochemical cell shown below is a concentration cell.
$M|{ M }^{ 2+ }$ (saturated solution of a sparingly soluble salt, $M{X} _{2})\parallel {M}^{2+}(0.001 mol{dm}^{-3})| M$.
The emf of the cell depends on the difference in concentrations of ${M}^{2+}$ ions at the two electrodes.
The emf of the cell at $298K$ is $0.099V$
The solubility product (${K} _{sp}:{mol}^{3}{dm}^{-9}$) of ${MX} _{2}$ at $298K$ based on the information available for the given concentration cell is: (take $2.303\times R\times 298/F=0.059V$)
- $1\times {10}^{-15}$
- $4\times {10}^{-15}$
- $1\times {10}^{-12}$
- $4\times {10}^{-12}$