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Thermal Expansion and Gas Properties
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At constant pressure how much fraction of heat supplied to gas is converted into mechanical work ?
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A
$\dfrac { \gamma -1 }{ \gamma } $
💡 Explanation:
At constant pressure, dQ = nCp dT and dW = P dV = nR dT. The fraction of heat converted to work is dW/dQ = (nR dT) / (nCp dT) = R/Cp. Since Cp = gammaR / (gamma-1), the fraction is R / (gammaR / (gamma-1)) = (gamma-1)/gamma.