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Molecular formula and valency - class-VII

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Quantitatively, formula represents:

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A
One molecule of the substance.
B
The actual number of atoms of each element in one molecule of the substance.
C
The number of parts by weight of the substance (molecular weight).
D
The number of parts by weight of each element.
💡 Explanation:

(A) One molecule of the substance

$\longrightarrow$ example $NaCl,C _2H _5OH$

(B) The actual number of atoms of each element in one molecule of the substance.
$\longrightarrow$ example $H _2O$ [water]
It shows that water contains $2$ atoms of hydrogen and $1$ atom of oxygen.

(C) The number by parts by weight of the substance [molecular weight]
$\longrightarrow$ Molecular weight can be determined by chemical formula as shown below:-
$CO _2$
one atom of carbon $\times$ mass of carbon + $2$ atoms of oxygen $\times$ mass of oxygen
$=1\times 12+2\times 16$
$=12+32$
$=44g/mol$.

(D) The number of parts by weight of each element $\longrightarrow$ example (1) $C _2H _5OH$ [ethanol] Molecular mass= $46$
(i) Each mole of ethanol contains $2$ moles of carbon
$=12\times2$
$=24g$
(ii) $1$ mole of oxygen atom
$=16\times 1$
$=16g$
(iii) $6$ moles of hydrogen atom
$=1\times 6$
$=6g$
These are present in $46g$ of ethanol
$\therefore$ Percentage of carbon=$\cfrac {24}{46}\times 100=52.17$%
Percentage of oxygen=$\cfrac {16}{46}\times 100=34.78$%
Percentage of hydrogen=$\cfrac {6}{46}\times 100=13.05$%

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