Redox and electrode processes - class-XI
Questions covering Daniel/Daniell cell electrochemistry including electrode potentials, EMF calculations, redox reactions, electron flow, and Faraday's laws of electrolysis.
Questions
The life span of a Daniel cell may increased by:
- large Cu electrode
- lowering of CuSO$ _{4}$ concentration
- lowering of ZnSO$ _{4}$ concentration
- large zinc electrode
Estimate the cell potential of a Daniel cell having $1.0 M - Zn^{2+}$ and originally having $ 1.0 M - Cu^{2+}$ after sufficient ammonia has been added to the cathode compartment to make the $ NH _{3}$ concentration 2.0 M. Given: $ _{zn^{2+}|Zn}^{0} = 0.76 V, E _{Cu^{2+}|Cu}^{0} = + 0.34 V, K _{f}$ for $ Cu (NH _{3}) _{4}^{2+} = 1 \times 10^{12}.$
- 1.10 V
- 0.704 V
- 0.396 V
- 1.496 V
The passage of electricity in the Daniel cell when Zn and Cu electrodes are connected
- from Cu to Zn inside the cell
- from Cu to Zn outside the cell
- from Zn to Cu inside the cell
- from Zn to Cu outside the cell
In a Daniel cell when $Cu$ and $Zn$ electrodes are connected current flows from:
- $Cu$ to $Zn$ within the cell
- $Cu$ to $Zn$ outside the cell
- $Zn$ to $Cu$ outside the cell
- all of the above
In the electrochemical cell $H _{2}(g),1atm|H^{+}(1M)||Cu^{2+}(1M)|Cu(s)$, which one of the following statements is true?
- H$ _{2}$ is cathode, Cu is anode
- Oxidation occurs at Cu electrode
- Reduction occurs at H$ _{2}$ electrode
- H$ _{2}$ is anode, Cu is Cathode
The standard EMF of a Daniel cell at 298 K is $E _{1}$. When the concentration of $ZnSO _{4}$ is 1.0 M and that of $CuSO _{4}$ is 0.01 M, the EMF becomes $E _{2}$ at 298 K. The correct relationship between $E _{1}$ and $E _{2}$ is
- $E _{1} = E _{2}$
- $E _{2}=0$
- $E _{1} > E _{2}$
- $E _{1} < E _{2}$
If a current of 1.0 A is drawn from the Daniel cell for 96.5 min, the cathode will gain in weight by (Cu = 63.5, Zn = 65.4)
- 1.905 g
- 1.962 g
- 3.81 g
- 3.924 g
If a battery of $1.6V$ is connected to Daniel cell, current flows:
- into the cell
- out of the cell
- neither in nor out of the cell
- both ways
- anode.
- cathode.
- lead oxide electrode.
- oxidizer.
- salt bridge.
- Both Assertion and Reason are true and Reason is the correct explanation of Assertion
- Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
- Assertion is true but Reason is false
- Assertion is false but Reason is true
- Both Assertion and Reason are false
For the cell $Zn(s)|Zn^{2+}(aq)||Cu^{+2}(aq)|Cu(s)$. The cell potential $E _{cell}$ can be increased.
- By increasing $[Cu^{+2}]$
- By increasing $[Zn^{+2}]$
- By decreasing $[Cu^{+2}]$
- By decreasing $[Zn^{+2}]$
In a Daniell cell:
- The chemical energy liberated during the redox reaction is converted to electrical energy
- The electrical energy of the cell is converted to chemical energy
- The energy of the cell is utilised in conduction of the redox reaction
- The potential energy of the cell is converted into electrical energy
Which one is not correct for e.m.f. of a galvanic cell?
- $E _{cell} = E _{OP _{anode}} + E _{RP _{cathode}}$
- $E _{cell} = E _{OP _{LHS}} + E _{RP _{RHS}}$
- $E _{cell} =$ higher oxidation potential - lower oxidation potential
- $E _{cell} =$ lower oxidation potential - higher oxidation potential
Identify the true statement regarding Daniel cell:
- Zinc ions flows across salt bridge
- ${K}^{+}$ ions move from salt bridge to $Cu/{Cu}^{+2}$ half cell
- Oxidation takes place at copper electrode
- Flow of current takes place from copper electrode to zinc electrode
For the galvanic cell, $Cu|Cu^{2+}||Ag^+|Ag$. Which of the following observations is not correct?
- Cu acts as anode and Ag acts as cathode
- Ag electrode loses mass and Cu electrode gains mass
- Reaction at anode, $Cu\rightarrow Cu^{2+}+2e^-$
- Copper is more reactive than silver
The negative Zn pole of Daniel cell, sending a constant current through a circuit, decreases in mass by 0.13 g in 30 minutes. If the chemical equivalent of Zn and Cu and 32.5 and 31.5 respectively, the increase in the mass of the positive Cu pole in this time is :
- 0.180 g
- 0.141 g
- 0.126 g
- 0.242 g
The passage of electricity in the Daniell cell when $Zn$ and $Cu$ electrodes are connected is from:
- $Cu$ to $Zn$ in the cell
- $Cu$ to $Zn$ outside the cell
- $Zn$ to $Cu$ outside the cell
- $Zn$ to $Cu$ in the cell
Daniel cell operates under nonstandard state conditions. If the equation of the cell reaction is multiplied by 2 then:
- $E$ and $E^o$ remain unchanged
- $E$ is doubled
- $n$ remains unchanged in Nernst equation
- $Q$ is halved in Nernst equation
For the Daniel cell involving the cell reaction${ Zn } _{ (s) }+{ { Cu }^{ +2 } } _{ (aq) }\rightleftharpoons { { { Zn }^{ +2 } } } _{ (aq) }+{ Cu } _{ (s) }$ the standard free energies of formation of ${ Zn } _{ (s) }$, ${ Cu } _{ (s) }$, ${ { Cu }^{ +2 } } _{ (aq) }$ and ${ { { Zn }^{ +2 } } } _{ (aq) }$ are 0, 0, 64.4 KJ/Mole and -154.0 KJ/Mole, respectively. Calculate the standard EMF of the cell?
- $2.13 Volts$
- $1.13 Volts$
- $2.26 Volts$
- $3.42 Volts$
Which of the following statement is TRUE for the electrochemical Daniel cell :
- Electron flow from Zinc electrode to Copper electrode.
- Current flows from zinc electrode to copper electrode.
- Cation moves towards copper electrode.
- Cation moves towards zinc electrode.