Reducing equation of straight line to standard form - class-X
reducing equation of straight line to standard form
Questions
- $1$
- $-1$
- $\dfrac{1}{2}$
- $2$
The equation of the line passing through $(-4, 3)$, parallel to the $3x+7y+6=0$
- 3x+7y-9=0
- 3x+7y+9=0
- 3x+7y+3=0
- 3x+7y+12=0
The slope and the y-intercept of the given line, $y-3x -6=0$ are respectively,
- $3, -6$
- $-3, -6$
- $3, 6$
- $-3, 6$
The slope and y-intercept of the following line are respectively
- $ slope=m=1\quad and\quad y-intercept=c=\frac { 5 }{ 2 } . $
- $ slope=m=1/5\quad and\quad y-intercept=c=\frac { 2 }{ 5 } . $
- $ slope=m=-1\quad and\quad y-intercept=c=\frac { 5 }{ 2 } . $
- $ slope=m=-1/5\quad and\quad y-intercept=c=\frac { 2 }{ 5 } . $
The slope and y-intercept of the following line are respectively
- $ slope=m=7/3\quad and\quad y-intercept=1.\\ $
- $ slope=m=-7\quad and\quad y-intercept=3.\\ $
- $ slope=m=-7/3\quad and\quad y-intercept=1.\\ $
- $ slope=m=7\quad and\quad y-intercept=3.\\ $
The slope and the y-intercept of the given line, $2x-3y = 7$ are respectively,
- $\dfrac{3}{2}, \dfrac{-3}{7}$
- $\dfrac{2}{3}, \dfrac{-7}{3}$
- $\dfrac{3}{2}, \dfrac{3}{7}$
- $\dfrac{2}{3}, \dfrac{7}{3}$
The slope and y-intercept of the following line are respectively
- $ slope=m=4\quad and\quad y-intercept=0.\\ $
- $ slope=m=-4\quad and\quad y-intercept=0.\\ $
- $ slope=m=1/4\quad and\quad y-intercept=0.\\ $
- $ slope=m=0\quad and\quad y-intercept=1/4.\\ $
The slope and y-intercept of the following line are respectively
- $ slope=m=\frac { -1 }{ 2 } \quad and\quad y-intercept=\frac { 1 }{ 4 } . $
- $ slope=m=2 \quad and\quad y-intercept=-\frac { 1 }{ 4 } . $
- $ slope=m=-\frac { 1 }{ 2 } \quad and\quad y-intercept=-\frac { 1 }{ 4 } . $
- $ slope=m=\frac { 1 }{ 2 } \quad and\quad y-intercept=\frac { 1 }{ 4 } . $
The slope and y-intercept of the following line are respectively
- $ slope=m=-\frac { 5 }{ 2 } \quad and\quad y-intercept=-\frac { 3 }{ 2 } . $
- $ slope=m=\frac { 5 }{ 2 } \quad and\quad y-intercept=\frac { 3 }{ 2 } . $
- $ slope=m=\frac { 5 }{ 2 } \quad and\quad y-intercept=-\frac { 3 }{ 2 } . $
- $ slope=m=-\frac { 5 }{ 2 } \quad and\quad y-intercept=\frac { 3 }{ 2 } . $
The slope and $y$-intercept of the following line are respectively
- slope $=m=-\dfrac { 5 }{ 8 } $ and $ y$-intercept $=\dfrac { 1 }{ 4 } $
- slope $=m=\dfrac { 5 }{ 8 } $ and $y$-intercept $=-\dfrac { 1 }{ 4 } $
- slope $=m=-\dfrac { 5 }{ 8 }$ and $ y$-intercept $=-\dfrac { 1 }{ 4 } $
- slope $=m=\dfrac { 5 }{ 8 } $ and $ y$-intercept $=\dfrac { 1 }{ 4 } $
For the equation given below, find the the slope and the y-intercept : $\displaystyle 3y=7$
- $\displaystyle 0 \ and \ \frac{7}{3}$
- $\displaystyle 0 \ and \ -\frac{7}{3}$
- $\displaystyle -\frac{7}{3} \ and \ 0$
- $\displaystyle \frac{7}{3} \ and \ 0$
$ax + by + c = 0$ does not represent an equation of line if ____.
- $a = c = 0, b \neq 0$
- $b = c = 0, a \neq 0$
- $a = b = 0$
- $c = 0, a \neq 0, b \neq 0 $
Find slope, x-intercept & y-intercept of the line 2x - 3y + 5 = 0
- $\dfrac{-5}{2},\dfrac{5}{3},\dfrac{2}{3}$
- $\dfrac{-5}{2},\dfrac{5}{3},\dfrac{1}{3}$
- $\dfrac{-3}{2},\dfrac{5}{3},\dfrac{2}{3}$
- $\dfrac{-5}{2},\dfrac{4}{3},\dfrac{2}{3}$
Find the slope and $y$-intercept of the line $2x + 5y = 1$
- slope $=$ $-\dfrac{2}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$
- slope $=$ $-\dfrac{1}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$
- slope $=$ $-\dfrac{2}{3}$, $y$-intercept $=$ $\dfrac{1}{5}$
- slope $=$ $-\dfrac{2}{5}$, $y$-intercept $= $ $\dfrac{2}{5}$
Find the slope and $y$-intercept of the line $-5x + y = 5$.
- slope $= 5, y$-intercept $= -5$
- slope $= 5, y$-intercept $= -4$
- slope $= 5, y$-intercept $= 5$
- slope $= 5, y$-intercept $= -1$
Find the slope and $y$-intercept of the line $0.2x - y = 1.2$
- slope $= 0.2$, $y$-intercept $= -1.2$
- slope $= 1.2$, $y$-intercept $= -1.2$
- slope $= 0.2$, $y$-intercept $= -2.2$
- slope $= 0.2$, $y$-intercept $= -1.3$
Find the slope and $y$-intercept of the line $2x + 2y = -2$
- slope = 1, y-intercept $= -3$
- slope = -1, y-intercept $= -1$
- slope = 1, y-intercept $= 3$
- slope = 1, y-intercept $= 1$
Find the slope and $y$-intercept of the line $x - y = 3$
- slope $= 2$, $y$-intercept $= -3$
- slope $= 0$, $y$-intercept $= -3$
- slope $= 1$, $y$-intercept $= -3$
- slope $= 1$, $y$-intercept $= 3$
A line in the $xy$-plane passes through the origin and has a slope of $\dfrac{1}{7}$. Which of the following points lies on the line?
- $\left(0, 7\right)$
- $\left(1, 7\right)$
- $\left(7, 7\right)$
- $\left(14, 2\right)$
Find an equation of the line through the points $(-3,5)$ and $(9,10)$ and write it in standard form $Ax+By=C$, with $A>0$
- $6x-10y=-75$
- $5x-12y=-75$
- $4x-11y=-65$
- $x-6y=-15$