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Functions and their graphs - class-XII
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If f is even function and g is an odd function, then $f _og$ is ............function.
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A
Even
💡 Explanation:
$fog$ function is an even function
Let $f\left(x \right)$ is a even function and $g \left( - x \right)$ is odd function.
So, $f\left( {g\left( { - x} \right)} \right) = f\left( { - g\left( x \right)} \right) = even$