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Sinusoidal current - class-X
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A 220 V, 50 Hz AC source is connected to an inductance of 0.2 H and resistance of 20 $\Omega$ in series. The current in the circuit is :
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A
$3.33 A$
💡 Explanation:
Given, V =220 volts, f=50 Hz, L =0.2 H, R = 20 $\Omega$
$X _L =2\pi fL=2 \times 3.14 \times 50 \times 0.2$
$= 100 \times 0.628 = 62.80\Omega$
$Z = \sqrt{X^2 _L + R^2} = \sqrt{(62.8)^2 + 20^2}$
$I = \displaystyle \frac{V}{Z} = \frac{220}{\sqrt{43473.84}} = 3.33A$