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Diagonal of cube and cuboid - class-X
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Is $(3,\,4,\,6)$ a pythagorean triplet?
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A
No
💡 Explanation:
$ {3}^{2} + {4}^{2} = 9 + 16 = 25 $
$ {6}^{2} = 36 $
Since, $ {3}^{2} + {4}^{2} \neq {6}^{2} , (3,4,6) $ is not a pythagorean triplet.