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Division of Line Segment in Given Ratio - Class X
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ABC is a triangle, the point P is on side BC such that $3\bar{BP}=2\bar{PC}$, the point Q is on the line $\bar{CA}$ such that $4\bar{CQ}=\bar{QA}$. If R is the common point $\bar{AP}$ & $\bar{BQ}$, then the ratio in which the fine joining CR divides $\bar{AB}$ is?
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A
$2:5$
💡 Explanation:
Using Menelaus' Theorem or vector geometry, the intersection of cevians in a triangle can be solved by setting up ratios of segments on the sides.