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Laws of heat transfer - class-XI online quiz
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The temperature of the black body that radiates heat at a rate of $459.27 \times 10^4 W m^{-2}$ is:
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A
3000K
💡 Explanation:
According to Stefan-Boltzmann law, the total energy radiated per unit surface area per unit time is E = sigma * T^4. Given E = 459.27 * 10^4 W/m^2 and taking Stefan's constant sigma approx 5.67 * 10^-8 W/m^2/K^4, solving for T gives T = (459.27 * 10^4 / 5.67 * 10^-8)^(1/4) = (8.1 * 10^12)^(1/4) = 3000 K.