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Multiply and divide - class-VIII
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If $n=2^3\times 3^4\times 7\times15^6$, then find the number of consecutive zeros in natural number n
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A
3
💡 Explanation:
Consecutive zeros are formed by factors of 10 (2 * 5). n = 2^3 * 3^4 * 7 * (3*5)^6 = 2^3 * 3^10 * 7 * 5^6. The number of pairs of (2, 5) is min(3, 6) = 3.