Reduction of carboxylic acids - class-XII
Reduction of carboxylic acids
Questions
$PhCOOH\xrightarrow{DIBALH} $
- $PhCHO$
- $PhO$
- $PhCH _2OH$
- None of these
How - $COOH$ can be converted into $CH _3$ group?
- $\;Na\;\&\;alcohol$
- $\;Zn+HCl$
- $\;LiAlH _4$
- $\;Hl\;\&\;red\;phosphorous$
Which of the following reagents can convert acetic acid into ethanol?
- $Sn + HCl$
- $H _{2} + Pt$
- $LiAlH _{4}+$ Ether
- $Na +$ Alcohol
Which of the following reduces carboxylic acid directly to primary alcohols?
- $LiAlH _{4}$
- $Na + C _{2}H _{5}OH$
- $\text{Lindlar's Catalyst}$
- $H _{2}$
Which of the following reaction is not the oxidation?
- $CH _{3} - CHO \rightarrow CH _{3}COOH$
- $C _{2}H _{5}OH \rightarrow CH _{3} - CHO$
- $C _{2}H _{5}OH \rightarrow CH _{3} - COOH$
- $CH _{3}COOH \rightarrow C _{2}H _{5}OH$
$RCOOH \rightarrow RCH _{2}OH$
- Zn/HCl
- Na - alcohol
- Aluminium isopropoxide and isopropyl
alcohol - LiAlH$ _{4}$
$CH _{3}COOH \xrightarrow[]{LiAlH _{4}}(A)\xrightarrow[H _{2}]{Ni} B$ In this reaction A and B respectively are :
- $CH _{3}OH and CH _{4}$
- $C _{2}H _{5}OH and C _{2}H _{6}$
- $CH _{3}CHO and C _{2}H _{5} OC _{2}H _{5}$
- $C _{2}H _{5}OH and CH _{3}OCH _{3}$
The reagent(s) used for converting ethanoic acid to ethanol is/are :
- $LiAlH _{4}$
- $BH _{3}$ in $THF$
- $PCl _{3}$
- $K _{2}Cr _{2}O _{7}/H^{+}$
Methyl alcohol when reacted with carbon monoxide using cobalt or rhodium as catalyst , compound $'A'$ is formed. $'A'$ on heating with HI in the presence of red phosphorus as catalyst $'B'$ is formed. $'B'$ is:
- $CH _3COOH$
- $CH _3CHO$
- $CH _3CH _2I$
- $CH _3CH _3$
Alcohols can be obtained from carboxylic acids by reduction using one of the following reagents:
- $LiAIH _{4}$
- $N/alcohol$
- $Zn/HCl$
- $H _{2}/Ni$
Which optically active compound on reduction with $\displaystyle LiAlH _{4}$ will give optically inactive compound?
- $CH _3-CH(OCH _3)-COOH$
- $CH _3-CH _2-CH(OH)-COOH$
- $CH _3-CH _2-CH(CH _2OH)-COOH$
- $CH _3-CH(OH)-CH _2-COOH$
The organic product formed in the reaction. $C _{6}H _{5}COOH \xrightarrow[(II)H _{3}O]{(I)LiAIH _{4}}$?
- $C _{6}H _{5}CH _{2}OH$
- $C _{6}H _{5}OHCH _{4}$
- $C _{6}H _{5}CH _{3} and CH _{3} OH$
- $C _{6}H _{5}CH _{3} and CH _{4} $
What happens when a carboxylic acid is treated with lithium aluminium hydride?
- Aldehyde is formed.
- Primary alcohol is formed.
- Ketone is formed.
- Grignard reagent is formed.
Consider the following reaction $CH _3-(CH _2) _{14}-COOH \overset{LiAlH _4}{\longrightarrow} ,X \overset{HCl}{\longrightarrow}$
Palmitic acid
$ Y \overset{1., Mg/Et _2O}{\underset{2., Oxirane}{\longrightarrow}} Z \overset{KMnO _4}{\longrightarrow} W$
The correct identity of the compounds is/are :
- $X \,is \,CH _3-(CH _2) _{14}-CH _2OH$
- $Y\, is \, CH _3-(CH _2) _{14}-CH _2Cl$
- $Z \,is\, CH _3-(CH _2) _{16}-CH _2OH$
- $W \, is\, CH _3-(CH _2) _{16}-CHO$