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Conjugate hyperbola - class-XII
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The
eccentricity of the hyperbola whose asymptotes are $3x + 4y = 2{\text{ and }}4x - 3y + 5 = 0$
AnswerClick to flip back
A
$\sqrt 2 $
💡 Explanation:
The asymptotes of a hyperbola differ from the hyperbola equation only by a constant term. Using the family of lines representing the asymptotes, we can find the angle between them and subsequently compute the eccentricity as sqrt(2) for a rectangular hyperbola where asymptotes are perpendicular.