SHM as projection of circular motion - class-XI
SHM as projection of circular motion
Questions
Two SHMs are represented by the equations
$y1=10sin(3\Omega t+\frac{\Omega }{4})$ and
$y2=5[sin3\Omega t+\sqrt{3}cos 3\Omega t]$. their amplitudes and in the ratio
- 1:2
- 2:1
- 1:3
- 1:1
A simple harmonic oscillator starts from extreme position and covers a displacement half of its amplitude in a time '$t$', the further time taken by it to reach mean position is
- $2t$
- $t$
- $ t/\sqrt{2} $
- $t/2$
The circular motion of a particle whose speed is constant is
- Periodic but not simple harmonic
- Simple harmonic but not periodic
- Periodic and simple harmonic
- Neither periodic not simple harmonic
Find the distance covered by a particle from time $t=0$ to $t=6\ \sec$. When the particle followsa the movement in straight line according to $y=a\cos \left(\dfrac {\pi}{4}\right)t$:-
- $a$
- $2a$
- $3a$
- $4a$
The particle executes SHM on a straight line. At two positions its velocity $u$ and $v$ while acceleration, $\alpha$ and $\beta$ respectively $[\beta > \alpha >0]$, the distance between the two positions will be:-
- $\dfrac{u^2+v^2}{\alpha+\beta}$
- $-\dfrac{u^2-v^2}{\alpha+\beta}$
- $\dfrac{u^2-v^2}{\alpha-\beta}$
- $\dfrac{u^2+v^2}{\beta-\alpha}$
To understand Simple Harmonic Motion as analogous to circular motion,
- we project the circular motion of the particle along any radius.
- we project the circulation motion of the particle along a chord.
- we project the circulation motion of the particle along the diameter.
- None of these.
The actual distance moved along the circle will be the distance moved by the projection on the diameter.
- less than
- equal to
- greater than
- None of these
The particle executes SHM on a straight line. At two positions its velocity $u$ and $v$ while acceleration, $\alpha$ and $\beta$ respectively $[\beta > \alpha >0]$, the distance between the two positions will be:-
- $\frac{u^2+v^2}{\alpha+\beta}$
- $-\frac{u^2-v^2}{\alpha+\beta}$
- $\frac{u^2-v^2}{\alpha-\beta}$
- $\frac{u^2+v^2}{\beta-\alpha}$
The period of a particle it is $8s$. At $t=0$ it is at the mean position. The ratio of the distance covered by the particle in first second and second will be
- $\cfrac { \sqrt { 2 } -1 }{ \sqrt { 2 } } $
- $\cfrac { 1 }{ \sqrt { 2 } } $
- $\cfrac { 1 }{ \sqrt { 2 } -1 } $
- $\left[ \sqrt { 2 } -1 \right] $
Simple harmonic motion is the projection of uniform circular motion on the
- $x$- axis
- $y$- axis
- reference circle
- any diameter of reference circle.