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SHM as projection of circular motion - class-XI
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Two SHMs are represented by the equations
$y1=10sin(3\Omega t+\frac{\Omega }{4})$ and
$y2=5[sin3\Omega t+\sqrt{3}cos 3\Omega t]$. their amplitudes and in the ratio
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A
2:1
💡 Explanation:
Compare the given equations with,
$y=a\sin \omega t$
Where a is amplitude of wave
Here, a1 = 10
a2 = 5
So the ratio is
$\dfrac{{{a} _{1}}}{{{a} _{2}}}=\dfrac{10}{5}=\dfrac{2}{1}$
Or $2:1$