Surface energy of a liquid - class-XI
surface energy of a liquid
Questions
What is the change in surface energy, when a mercury drop of radius $r$ splits up into 1000 droplets of radius $r$?
- $8pr^2t$
- $28pr^2t$
- $16pr^2t$
- $36pr^2t$
Two soap bubbles have radii in the ratio of $4:3$. What is the ratio of work done to blow these bubbles?
- 4:3
- 16:9
- 9:16
- 3:4
W is the work done, when a bubble of volume V is formed from a solution. How much work is required to be done to form a bubble of volume 2V?
- $2W$
- $W$
- $2^{1/3}W$
- $2^{2/3}W$
The surface energy of a liquid drop of radius r is proportional to:
- $r^3$
- $r^2$
- r
- $\dfrac {1}{r}$
A mercury drop of radius 1 cm is broken into 106 droplets of equal size. The work done is
$(T = 35 10^{-2} N/m)$- $1.615\times 10^{-3}J$
- $4.35\times 10^{-4}J$
- $1.615\times 10^{-6}J$
- $4.35\times 10^{-8}J$
Surface tension of a soap solution is $1.9 10^{-2} N/m.$ Work done in blowing a bubble of 2.0cm diameter will be
- $7.6 10^{-6} J$
- $15.2 10^{-6} J$
- $16 10^{-6} J$
- $2.5 10^{-6} J$
The surface tension of a soap solution is $0.035 N/m$. the energy needed to increase the radius of the bubble from $4$ cm to $6$ cm is
- $1.75\times 10^{-3} J$
- $1.510^{-2} J$
- $310^{-3} J$
- $1.510^{-4} J$
Two drops of a liquid are merged to from a single drop. In this process-
- Energy is released
- Energy is absorbed
- Energy remains constant
- First B then A
Two soap bubbles of radii 4 cm and 3 cm respectively coalesce under isothermal conditions to form a single bubble. What is the radius of the new single bubble?
- $3 cm$
- $4 cm$
- $5 cm$
- $6 cm$
A square frame of length $L$ is immersed in soap solution and taken out. The force experienced by the square plate is
- $TL$
- $2TL$
- $4TL$
- $8TL$
A spherical water drop of radius $R$ is split up into $8$ equal droplets. If $T$ is the surface tension of water, then the work done in this process is-
- $4\pi R^2T$
- $8\pi R^2T$
- $48\pi R^2T$
- $2\pi R^2T$
A drop of oil is placed on the surface of water. Which of the following statement is correct?
- It will remain on it as a sphere
- It will spread as a thin layer
- It will partly be as spherical droplets and partly as thin film
- It will float as distorted drop on the water surface.
One thousand small water droplets of equal size combine to form a big drop. The ratio of the final surface energy to the initial surface energy is: (Surface tension of water = 70 dyne/cm)
- 10:1
- 1000:1
- 1:10
- 1:1000
Two spherical soap bubbles of a radii $r _1$ and $r _2$ in vacuum coalesce under isothermal conditions. The resulting bubble has the radius $R$ such that
- $R=r _1+r _2$
- $R^2 ={ r _1^2 + r _2^2}$
- $R=\dfrac{r _1+r _2}{r _2}$
- none of these
What is the change in surface energy, when a mercury drop of radius $R$ splits up into $1000$ droplets of radius $r$?
- $8\pi R^2T$
- $16\pi R^2T$
- $24\pi R^2T$
- $36\pi R^2T$
Potential energy of a molecule on the surface of a liquid is as compared to another molecule inside of the liquid is
- More
- Less
- Both a and b
- None of these