### Intersection of two straight lines - class-XI

Description: intersection of two straight lines | |

Number of Questions: 15 | |

Created by: Rani Rajan | |

Tags: coordinate geometry maths the straight line functions and graphs two dimensional analytical geometry |

The direction with $+x-axis$ in which a straight line will be drawn through the point $\left(1,2\right)$ so that its point of intersection with the line $x+y=4$ may be at a distance $\sqrt { \dfrac { 2 }{ 3 } }$ from the point $\left(1,2\right)$ can be:

The equation $2x^2 + 5xy + 3y^2 + 6x + 7y + 4 = 0$ represents a pair of straight lines.

The curve satisfying the equation $\dfrac { dy }{ dx } =\dfrac { y(x+{ y }^{ 3 }) }{ x({ y }^{ 3 }-x) } $ and passing through the point (4, -2) is

if the equation ${ 4x }^{ 2 }+2\sqrt { 3xy } +{ 2y }^{ 2 }-1=0$ becomes ${ 5x }^{ 2 }+{ y }^{ 2 }=1,\quad$ when the axes are rotar trough an angle ${ 45 }^{ 0 }$ , then the original equation of the curve is :'

The equation of a straight line passing through a point $(-5,4)$ and which cuts off an intercept of $\sqrt{2}$ units between the lines $x+y+1=0$ and $x+y-1=0$ is

Equation of a straight line passing through the point $(4, 5)$ and equally inclined to the lines $3x=4y+7$ and $5y=12x+6$ is?

The number of values of $c$ such that the straight line $y=4x+c$ touches the curve $x^{2}+4y^{2}=4$, is

The equation of a straight line passing through the point (-5,4) and which cuts off an intercept of $\sqrt { 2 } $ unit between the lines $x+y+1=0$ and $x+y-1=0$ is:

The equation of a straight line passing through the point (-5, 4) and which cuts off in intercept of $\sqrt { 2 } $ unit. between the lines $x+y+1=0$ and $x+y-1=0$ is:

A line passing through the points of intersection of $x+y=4$ and $x-y=2$ makes an angle $\tan^{-1}(3/4)$ with the x-axis. It intersects the parabola $y^2=4(x-3)$ at points $(x _1, y _1)$ and $(x _2, y _2)$ respectively. Then $|x _1-x _2|$ is equal to?

If the lines joining the origin to the intersection of the line $y=mx+ 2$ and the curve $x^{2}+ y^{2}= 1$ are at right angles, then

If the straight lines joining the origin and the points of intersection of the curve $5x^2 + 12xy -6y^2 + 4x -2y + 3 = 0$ and $x + ky -1 = 0$ are equally inclined to the co-ordinate axis, then the value of $k$

The lines joining the origin to the point of intersection of $3x^2 + mxy - 4x + 1 = 0$ and $2x + y - 1= 0$ are at right angles. Then which of the following is/are possible value/s of $m?$

Find the equation of the lines joining the origin to the points of intersection of the curve $2x^2 + 3xy -4x + 1 = 0$ and the line $3x + y = 1$