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Area of complex plane figures - class-X
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Find the area of equilateral triangle inscribed in a circle of unit radius.
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A
$\dfrac {3\sqrt { 3 } }{4}$
💡 Explanation:
The radius of circumcircle of equilateral triangle is $\dfrac 23h=1\h=\dfrac 32$
The side of equilateral triangle is given as $\dfrac{4h}{\sqrt 3} \\dfrac{4}{\sqrt 3}\times \dfrac 32=2\sqrt 3$
The area of triangle is given as $\dfrac {\sqrt 3}{4}(2\sqrt 3)^2=3\sqrt 3$