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Simple moving average - class-X
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A train running at $\dfrac{7}{{11}}$ of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed ?
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A
8 hours
💡 Explanation:
Let s be the actual speed of the train and d be the distance that needs to be covered to reach that place.
Here, speed$=\dfrac{Distance}{Time}$
As per question,
The train is running at $\dfrac{7}{11}$ of its own speed and reaches the place in $22$ hrs.
$\therefore d=\dfrac{7}{11}s.22$
$\Rightarrow d=14s$ ………..$(1)$
Let t be the time taken by the train to reach the place with its actual speed.
$\therefore d=st$ ………..$(2)$
from $(1)$ and $(2)$, we get
$14s=st$
$\Rightarrow t=14$ hours
$\therefore$ Time that could be saved$=22-14$
$=8$hrs.