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Mechanical Engg. (GATE) 2005
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The right circular cone of largest volume that can be enclosed by a sphere of 1 m radius has a height of
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A
$\frac{4}{3}m$
💡 Explanation:
$\frac{d^2V}{dH^2}=\frac{1}{3}\pi[4-0]>0(Minima)\\
\text{So, for the largest volume of cone, the value of H should be 4/3}$