To answer this question, we need to understand the concepts of thread synchronization and the methods wait(), notify(), and notifyAll().

Option A) wait() - This option is correct. The wait() method is used to suspend the execution of a thread and releases the lock it holds. It allows other threads to acquire the lock and continue their execution. The thread will remain in a suspended state until another thread calls the notify() or notifyAll() method.

Option B) notify() - This option is incorrect. The notify() method is used to wake up a single thread that is waiting on the same object. It does not stop the execution of a thread, but rather notifies one waiting thread to resume execution.

Option C) notifyAll() - This option is incorrect. The notifyAll() method is used to wake up all threads that are waiting on the same object. It also does not stop the execution of a thread but rather notifies all waiting threads to resume execution.

Option D) exits synchronized code - This option is incorrect. Exiting synchronized code does not directly stop the execution of a thread. It simply releases the lock it holds and allows other threads to acquire the lock and continue their execution.

Therefore, the correct answer is option A) wait(). This option directly stops the execution of a thread by suspending it until another thread calls the notify() or notifyAll() method.

Please let me know if you need any further clarification.

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• Wrong explanation

To answer this question, you need to understand the java.lang.Runnable interface.

The java.lang.Runnable interface is used to define a task that can be executed by a thread. It contains only one method that must be implemented by any class that implements this interface.

The method that must be defined by a class implementing the java.lang.Runnable interface is:

Option B) public void run()

This method represents the task that will be executed when a thread is started. It does not take any arguments and does not return any value. The implementation of this method should contain the code that defines the task to be performed by the thread.

Option A) void run() - This option is incorrect because the run() method must be defined as public when implementing the java.lang.Runnable interface.

Option C) public void start() - This option is incorrect because the start() method is not part of the java.lang.Runnable interface. The start() method is a method of the Thread class, which is used to start a new thread.

Option D) void run(int priority) - This option is incorrect because the run() method in the java.lang.Runnable interface does not take any arguments.

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To answer this question, we need to understand the concepts related to threads.

In computer programming, a thread is a sequence of instructions that can be executed independently of the main program. Each thread has its own stack and execution context, allowing multiple threads to run concurrently.

In the given options, the correct answer is A) run().

The run() method is the entry point for a thread when it is executed. It contains the body of the thread and defines the code that will be executed by the thread. The run() method should be overridden in a class that extends the Thread class or implements the Runnable interface.

Option B) start() is used to start a thread by invoking its run() method. It does not contain the body of the thread.

Option C) stop() is used to stop a thread, but it is considered unsafe and deprecated in most programming languages.

Option D) main() is the entry point for the main program, not for a thread. It is executed by the main thread.

Therefore, the correct answer is A) run(). This option is correct because it contains the body of the thread.

Please select the most appropriate option.

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• Wrong explanation

To answer this question, you need to understand how threads are registered in a thread scheduler.

Option A) run() - This option is incorrect because the run() method is responsible for the code that will be executed when the thread is started, but it does not register the thread in the thread scheduler.

Option B) construct() - This option is incorrect because there is no specific method named construct() for registering a thread in a thread scheduler.

Option C) start() - This option is correct because the start() method is used to register a thread in a thread scheduler. When the start() method is called, the thread is added to the thread scheduler's queue and will be executed by the scheduler when its turn comes.

Option D) register() - This option is incorrect because there is no specific method named register() for registering a thread in a thread scheduler.

The correct answer is C) start(). This option is correct because the start() method is used to register a thread in a thread scheduler.

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• Wrong explanation

To answer this question, you need to understand the concept of multi-threading in Java. The wait(), notify(), and notifyAll() methods are used for inter-thread communication and are defined in the Object class.

Let's go through each option to understand why it is correct or incorrect:

Option A) Object - This option is correct because the wait(), notify(), and notifyAll() methods are defined in the Object class. Every class in Java is a subclass of the Object class, and therefore, these methods are available in all classes.

Option B) Thread - This option is incorrect because the Thread class is responsible for creating and managing threads, but it does not define the wait(), notify(), and notifyAll() methods.

Option C) Runnable - This option is incorrect because the Runnable interface is used to define a task that can be executed by a thread. It does not define the wait(), notify(), and notifyAll() methods.

Option D) Class - This option is incorrect because the Class class is used to represent classes and interfaces in Java. It does not define the wait(), notify(), and notifyAll() methods.

The correct answer is Option A) Object. This option is correct because the wait(), notify(), and notifyAll() methods are defined in the Object class.

Therefore, the correct answer is Option A) Object.

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• Wrong explanation