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If the diameter of a wire is increased by 10%, by how much per cent approximately, will its length be decreased, if the volume remains the same?
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A
17
💡 Explanation:
Volume V = π(d/2)^2 * h. If d increases by 10% (1.1d), the new area is 1.21 times the old area. To keep volume constant, the new length must be 1/1.21 of the old length (~0.826), a decrease of ~17.36%.