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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
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A
10
💡 Explanation:
Let C's age be x. Then B's age is 2x (twice as old as C), and A's age is 2x+2 (two years older than B). The equation is: x + 2x + (2x+2) = 27, which simplifies to 5x + 2 = 27, so 5x = 25 and x = 5. Therefore, B's age = 2x = 10 years. This is a standard age-related algebra problem.