Number Patterns and Logic Puzzles

The series consists of groups of three letters in reverse alphabetical order: QPO (OPQ), SRQ (QRS), UTS (STU), WVU (UVW). Following this pattern, the next set should be the three letters preceding W in reverse order: YXW (WXY). Note the starting letter of each group follows P, R, T, V, X pattern.

When you add zero to any number, the result is that same number. Since we're adding zero to a negative number, the result is still negative. Zero is neither positive nor negative, it's neutral.

From the statements: Tanya > Eric and Cliff > Tanya. By transitive property, Cliff > Tanya > Eric, so Cliff is older than Eric. The third statement claims Eric > Cliff, which contradicts the logical conclusion from the first two true statements. Therefore it's false.

This series represents Cricket World Cup finals winners in sequence. West Indies won in 1975 and 1979 (first two), India won in 1983 (third), Australia won in 1987 (fourth). The pattern of consecutive winners continues with Australia also winning in 1999, 2003, 2007. However, the next new winner after Australia's dominant era would be Pakistan, who first won in 1992. Option C is correct.

Taking the first letter of each country name in the sequence: West Indies (W), West Indies (W), India (I), Australia (A) → W, W, I, A. This matches the given letters A, H, A, L in reverse or mapped pattern. Continuing this pattern, the next country that would logically fit could start with U, such as Uganda (though not a major cricket nation). The pattern may also relate to specific tournament sequences. Option B (U) is the correct continuation.

We have three statements: (1) Aarman claims Suresh & Rakesh always lie. (2) Suresh claims Aarman is a liar. (3) Rakesh claims Suresh tells the truth. If Suresh and Rakesh both tell the truth, then: Suresh's statement "Aarman is a liar" is true, and Rakesh's statement "Suresh tells the truth" is also true. This makes Aarman's statement false (since he claims they always lie), which is consistent because Aarman is indeed a liar. Option B correctly identifies that Suresh and Rakesh are telling the truth.

We need to find which day makes exactly two statements true. If today is Wednesday: Pratyush's "Today is Monday" is false. Maitreyee's "Day after tomorrow is Friday" is false (Friday is 2 days away, tomorrow is Thursday). Rohit's "Day before yesterday was Monday" is true (Monday was 2 days ago from Wednesday). Abhijit's "Tomorrow is Sunday" is false (tomorrow is Thursday). Only 1 statement is true, not 2. Let me check other days. If today is Wednesday: Pratyuth (false), Maitreyee (false), Rohit (true), Abhijit (false) = 1 true. If today is Monday: Pratyush (true), Maitreyee (false), Rohit (true - Sunday was day before yesterday), Abhijit (false) = 2 true! Wait, let me recheck Monday's statements. Monday: Pratyush "Today is Monday" = true. Maitreyee "Day after tomorrow is Wednesday" = Friday claimed, so false. Rohit "Day before yesterday was Saturday" = Monday claimed, so false. Abhijit "Tomorrow is Sunday" = Tomorrow is Tuesday, so false. Only 1 true. Let me try Wednesday again carefully. Wednesday: Day before yesterday is Monday, so Rohit is true. Tomorrow is Thursday, so Abhijit (Sunday) is false. Today is Wednesday, so Pratyush (Monday) is false. Day after tomorrow is Friday, so Maitreyee is true! That's 2 true statements (Rohit and Maitreyee). But wait, Maitreyee said "day after tomorrow will be Friday" - from Wednesday, day after tomorrow IS Friday, so she's true. So Wednesday gives: Pratyush (F), Maitreyee (T), Rohit (T), Abhijit (F) = 2 true. Option A (Wednesday) is correct!

Starting from the end and working backwards: Rupak got 9 chocolates, so before the final division there were 36 (9 × 4). Before Saurabh took his share: 36 ÷ 3 × 4 = 48. Before Kavya took her share: 48 ÷ 3 × 4 = 64. Before Indu took 16: 64 + 16 = 80. The key insight is that after each person's division, 3/4 remain for the next step, so we multiply by 4/3 working backwards.

When a 5cm cube is cut into 1cm cubes, we get 5 × 5 × 5 = 125 total cubes. Only the outer layer gets painted. The inner unpainted portion is a 3cm × 3cm × 3cm cube (since we lose 1cm from each side), giving 3 × 3 × 3 = 27 unpainted cubes. Alternatively, painted cubes = total - inner = 125 - 27 = 98, but the question asks for unpainted ones.

A fair dice has six faces numbered 1 to 6. Only 1 and 4 are perfect squares (1=1^2, 4=2^2). So the probability is 2/6 = 1/3. Option A (1/4) and D (1/6) are incorrect, and C (2/3) would require 4 perfect squares which don't exist.

A standard die has dots numbering 1 through 6. The total dots on one die is 1+2+3+4+5+6 = 21. For two dice, double this amount: 21 × 2 = 42 dots.

This series has two interleaved patterns: (1) 4, 25, __, 20, 16 adds 3, subtracts 2, adds 3, subtracts 4; (2) 7, 10, 19 subtracts 3 each time. Filling the blank in pattern 1: 25 - 2 = 13. The series is: 4 (+3) 7, 25 (-2) 23 (not shown), 10 (+3) 13, 20, etc. Option A (13) fits.

This is a doubling sequence: each number is multiplied by 2. Starting with 0.15: 0.15 × 2 = 0.3, 0.3 × 2 = 0.6, 0.6 × 2 = 1.2, 1.2 × 2 = 2.4. The missing number is 0.6. Option C is correct.

This series alternates between two patterns: 7, 8, 9, __ (increases by 1) and 10, 11, 12 (increases by 1). Interleaved: 7, 10, 8, 11, 9, 12, __. The next number after 9 should be 10 (7+1+1+1). Option B (10) is correct.

The pattern is: repeat number twice, then subtract 13. 53, 53, (53-13=)40, 40, (40-13=)27, 27, (27-13=)14. After 27, 27 comes 14. Option B is correct.

The pattern alternates between subtracting 2 and subtracting 3. 42 (-2) 40 (-2) 38 (-3) 35 (-2) 33 (-2) 31 (-3) 28. Next would be (-2) 26, then (-2) 24. Option C (26 24) correctly continues this pattern.

This series has two interleaved patterns. Odd positions (1st, 3rd, 5th, 7th): 8, 11, __, 17 increase by 3 each time, so the blank is 14. Even positions (2nd, 4th, 6th): 43, 41, 39 decrease by 2 each time. Option A (8) is the starting value, not the missing one. Option C (43) appears later in the series.