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Mixed Test (Maths)
Let the transportation cost of red, blue, yellow and green toys be Rs. 15, Rs. 20, Rs. 25 and Rs. 30, respectively. Then, the difference between the total cost of transportation of all the toys and the cost of transportation of green toys is
Directions: Read the following passage and answer the given question.
Let there be four colours of toys in a shop, i.e. red, green, blue and yellow. There are 101 toys of red colour. The number of blue toys is 4 less than the number of green toys. The number of yellow toys is 3 more than the number of red toys and the number of green toys is 10 less than the number yellow toys. Now, let k, l, m and n be the numbers of red, blue, yellow and green toys, respectively.
No. of red toys = 101
No. of yellow toys = 101 + 3 = 104
No. of green toys = 104 - 10 = 94
No. of blue toys = 94 - 4 = 90
Total transportation cost of all the toys = Rs. (101 x 15 + 90 x 20 + 104 x 25 + 94 x 30)
= Rs. (1515 + 1800 + 2600 + 2820)
= Rs. 8735
Total cost of transportation of green toys = Rs. (30 x 94)
= Rs. 2820
Therefore, required difference in the cost = Rs. (8735 - 2820) = Rs. 5915