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Electrostatics
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A regular hexagon with each side equaling 10 cm has a charge 5 μC at each of its vertices. Calculate the potential at the centre of the hexagon.
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A
2.7 x 106 V
💡 Explanation:
Given
a = 10cm = 0.10m; q =5 μC = 5 X 10-6 C
.V = Kq / r
Distance of centre from vertex for a regular hexagon is 10 cm.
V= 6 Kq/r
= 6 x 9 x109 x 5 x 10-6 /0.10
= 2.7 x 106 V