Profit, Loss and Discount

SP = 456.30 and Loss = 22%

CP = (SP * 100)/(100 - Loss%)

= (456.30 * 100)/(100 - 22)

= 585

So, CP of the article is Rs. 585. 

Now, the profit is 30%. 

Then, SP = CP(100 + Profit%)/100. 

= 585(100 + 30)/100 

= 760.50

So, the SP at 30% profit is 760.50.

Here, the sale price of the two watches is the same.

Gain% = loss% = 11%

In such a case, there is always a loss. 

To find overall loss%, use this shortcut formula: 

Overall % loss = (x/10)²

= (11/10)²

= 1.21%

Total number of bags = 120

Remaining bags = 100 - 50 - 50 = 20

To find overall profit/loss %, use this shortcut formula: 

%Gain or %loss on the whole property = Sum of product of quantity and respective gain or loss%/amount of whole property 

10 = (50 * 20 - 50 * 5 - 20 * x)/120

x = +12.5% (profit) 

SP of remaining bags = 112.5 * 500/100 = Rs. 562.50 per bag

To find the answer of this question, use this shortcut formula,

(100 + G)/(100 + X) = True length/False length 

(100 + G)/100 = 100/85 (since he sells at cost price, so x = 0) 

G = 17.65%

So, his required gain is 17.65%.

According to question,

32 * CP = 20 * SP

SP/CP = 32/20 = 8/5 

Now, use this shortcut formula:

Gain% = (SP/CP - 1) * 100

= (8/5 - 1) * 100

 = 60%

MP = Rs. 320, Profit = 36%, Discount = 15%

SP = 320 - 320 * 15/100 = Rs. 272

CP = (SP * 100)/(100 + Profit%) 

= (272 * 100)/(100 + 36) = Rs. 200

Find the equivalent discount with this shortcut formula:

Single equivalent discount = x + y - xy/100 

= 12 + 5 - 12 * 5/10 

= 16.4%

Net selling price = 300 - 300 * 16.4/100 

= 250.80

So, a customer will have to pay Rs. 250.80.

Let %gain on first almirah (g) be 12.5% and %loss on second almirah (l) be 10%.

Then, overall profit/loss% = 100 - (100 + g)(100 - l)/[(100 + g) + (100 - l)] 

= 100 - (100 + 12.5)(100 - 10)/[(100 + 12.5) + (100 -10)] 

= 100 - 100 

= 0%

So, there is no profit and no loss.

SP of 1 orange = Rs. 1/35

Now, apply this shortcut formula,

S1/(100 + X1) = S2/(100 + X2) 

(X1 and X2 is profit or loss%) 

(1/35)/(100 - 4) = S2/(100 + 12) 

S2 = 1/30 

Now, let y oranges be sold for a rupee. Then,

(1/30) * y = 1 

y = 30 

So, the required number of oranges is 30.

Let the SP of rice per kg be Rs. x.

Loss = CP - SP

4 * x = 720 - 12 * x

x = 45

So, the selling price of rice per kg is Rs. 45.

Let the CP of the book be Rs. x. 

Now, if the profit = 30% 

Then SP = CP(100 + Profit)/100 

= x(100 + 30)/100 

= 130x/100 

If the CP is 10% less and SP is Rs. 8 less,

Then CP = X - X * 10/100 = 90X/100

Now, according to the question,

[90x(100 + 40)]/(100 * 100) = 130x/100 - 8 

After solving this equation,

x = 200 

So, cost price of the book is Rs. 200.

Let the CP of goods be Rs. x.

MP has been marked y% above the CP. 

So, MP of goods = x + xy/100 

Now, according to question,

(x - xy/100) - (x - xy/100) * (12/100) = 130x/100 

After solving this equation, we get

y = 47.73%

So, the marked price will have to fixed 47.73% above the cost price.

Let the CP of the car be Rs. x  lakh and loss be Rs. y lakh. 

Then, loss = CP - SP

y = x - 3 -------------------(1) 

Again y - 0.40 = 5.60 - x --------------------(2) 

After solving, we get 

x = 4.50 and y = 1.5

So, the CP of the car Rs. 4.50 lakh.

Let the printed price of the book be Rs. x.

The selling price of the book at 5% discount = 95x/100 

CP of the book = (SP * 100)/(100 + Profit%)

= (95x * 100)/120 = 95x/120 

Now, ratio = (95x/120)/x = 19 : 24

Use this shortcut formula,

Real profit% (% profit on CP) = % profit on SP * 100/(100 - % profit on SP) 

= (14 * 100)/(100 - 14) 

= 16.28%