To answer this question, let's go through each statement and determine if it is true or false:

A. When TIME is added to a JOB statement, the entire job run time is limited to that amount. This statement is true. When the TIME parameter is specified on the JOB statement, the job's execution time is limited to that amount. If the time limit is exceeded, the job will be terminated.

B. When REGION=0 is coded, the job will not execute due to the fact that no working storage. This statement is false. When REGION=0 is coded on the JOB statement, it sets the region size for the job to zero. This means that the job will bypass any region checks, allowing it to execute even if there is no working storage available. However, the job may face issues due to lack of sufficient memory.

C. The COND parameter on JOB level will place the same condition on every EXEC statement. This statement is true. The COND parameter on the JOB statement allows you to specify a condition that applies to all subsequent EXEC statements within the job. If the condition evaluates to false, the associated EXEC statement will not be executed.

D. TYPRUN=SCAN means that the entire JCL script will be checked for syntax and value. This statement is false. TYPRUN=SCAN is used to perform a syntax check on the JCL script, but it does not check for the validity of values or perform value substitutions. The purpose of TYPRUN=SCAN is to identify any syntax errors in the JCL without actually executing the job.

Therefore, the correct statements are: A. When TIME is added to a JOB statement, the entire job run time is limited to that amount. C. The COND parameter on JOB level will place the same condition on every EXEC statement.

The correct answer is A,C.

• Thanks
• Wrong explanation

To answer this question, you need to understand the COND parameter in job control language (JCL) statements.

The COND parameter is used to specify a condition that determines whether a jobstep or job is to be executed. It takes the form of COND=(expression,condition), where expression is the condition to be evaluated and condition is the comparison operator.

In this case, you want the jobstep to be executed only if the previous jobstep has a return code of strictly less than 8. The correct option is A) COND=(8,LE).

Explanation for each option:

Option A) COND=(8,LE) - This option is correct because it specifies that the jobstep should be executed if the return code of the previous jobstep is less than or equal to 8. Since you want it to be strictly less than 8, this condition will be satisfied.

Option B) COND=(8,GE) - This option is incorrect because it specifies that the jobstep should be executed if the return code of the previous jobstep is greater than or equal to 8. This is the opposite of what you want.

Option C) COND=(8,LT) - This option is incorrect because it specifies that the jobstep should be executed if the return code of the previous jobstep is less than 8. This condition will not be satisfied if the return code is exactly 8.

Option D) COND=(8,GT) - This option is incorrect because it specifies that the jobstep should be executed if the return code of the previous jobstep is greater than 8. This condition will not be satisfied if the return code is less than or equal to 8.

Therefore, the correct answer is A) COND=(8,LE). This option ensures that the jobstep is executed only if the previous jobstep has a return code of strictly less than 8.

• Thanks
• Wrong explanation

To answer this question, we need to understand the syntax and meaning of the given JCL (Job Control Language) statement.

In the given JCL statement, each step is specified with an EXEC statement followed by the PGM (Program) parameter. The TIME parameter is used to specify the maximum CPU time allowed for each step. If the TIME parameter is not specified, the default time limit is used.

Let's go through each option to understand why it is correct or incorrect:

Option A) Step 1 can use 6 seconds of CPU time. This option is correct because the TIME parameter for Step 1 is specified as (,6), which means that Step 1 is limited to 6 seconds of CPU time.

Option B) Step 2 has no time limitations. This option is incorrect because there is no TIME parameter specified for Step 2. Without a TIME parameter, the default time limit will be used, which is usually a system-defined value.

Option C) Step 3 can use 15 seconds of CPU time. This option is incorrect because the TIME parameter for Step 3 is specified as (,15), which means that Step 3 is limited to 15 seconds of CPU time.

Option D) Each step is limited to its specifically mentioned time, but the entire job can only use 10. This option is correct because the TIME parameter for the entire job is specified as (,10), which means that the entire job is limited to 10 seconds of CPU time. Each step can use its specifically mentioned time limit, but the total CPU time used by all the steps combined cannot exceed the time limit specified for the job.

Therefore, the correct answer is A,D.

• Thanks
• Wrong explanation

To determine which of the given equations are correct, let's analyze each option one by one:

Option A) DISP=(,PASS) is equivalent to DISP=(NEW,PASS,KEEP) This option is incorrect. In the first equation, DISP=(,PASS), the first parameter is empty, indicating that the dataset is not being changed. However, in the second equation, DISP=(NEW,PASS,KEEP), the first parameter is "NEW", indicating that the dataset is being created or replaced. Therefore, the two equations are not equivalent.

Option B) DISP=(,,KEEP) is equivalent to DISP=(NEW,DELETE,KEEP) This option is correct. In both equations, DISP=(,,KEEP) and DISP=(NEW,DELETE,KEEP), the third parameter is "KEEP", indicating that the dataset is being kept. The first and second parameters are not relevant to whether the equations are equivalent. Therefore, the two equations are equivalent.

Option C) DISP=(,,CATLG) is equivalent to DISP=(OLD,CATLG,CATLG) This option is incorrect. In the first equation, DISP=(,,CATLG), the third parameter is "CATLG", indicating that the dataset is being cataloged. However, in the second equation, DISP=(OLD,CATLG,CATLG), the third parameter is "CATLG" again, indicating that the dataset is being cataloged twice. Therefore, the two equations are not equivalent.

Option D) DISP=(OLD,,) is equivalent to DISP=(OLD,KEEP,KEEP) This option is correct. In both equations, DISP=(OLD,,) and DISP=(OLD,KEEP,KEEP), the first parameter is "OLD", indicating that the dataset is being retained. The second and third parameters are not relevant to whether the equations are equivalent. Therefore, the two equations are equivalent.

Therefore, the correct equations are B) DISP=(,,KEEP) is equivalent to DISP=(NEW,DELETE,KEEP) and D) DISP=(OLD,,) is equivalent to DISP=(OLD,KEEP,KEEP).

• Thanks
• Wrong explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) A concatenation of datasets can be used for input, to use both DD entries describing sequential datasets and DD. This option is correct because concatenating datasets allows you to combine multiple datasets into one, and you can use DD (Data Definition) entries to describe these sequential datasets as input.

Option B) A concatenation of datasets can be used to write multiple output datasets. This option is incorrect because concatenating datasets is typically used for combining datasets as input, not for writing multiple output datasets.

Option C) A concatenation of datasets can contain a dummy dataset in the input, which will indicate the end of the input. This option is correct because you can include a dummy dataset in the concatenation of datasets to indicate the end of the input. This is useful when reading the concatenated datasets, as it provides a way to determine when to stop reading.

Option D) A concatenation of datasets, stored on different device types, cannot be used for input. This option is incorrect because a concatenation of datasets can be used for input regardless of the device types on which the datasets are stored. The device types do not restrict the usage of concatenated datasets as input.

The correct answers are A and C. These options are correct because a concatenation of datasets can be used for input, allowing you to use both DD entries describing sequential datasets and include a dummy dataset to indicate the end of the input.

• Thanks
• Wrong explanation

To answer this question, we need to understand how symbolic parameters work in JCL (Job Control Language).

In JCL, symbolic parameters are placeholders that can be replaced with actual values during job execution. The structure of symbolic parameters is typically denoted by an ampersand (&) followed by the parameter name.

Let's go through each option to determine which ones will result in the desired output of "TBISUSR.JCLCRS.DATA1":

Option A) &GROUP&DIV.&SUBJCRS.&TYPE&NMBR This option will result in "TBISUSRJCLCRSDATANMBR" because there are no period (.) separators between the symbolic parameters.

Option B) &GROUP&DIV..&SUBJ.CRS.&TYPE&NMBR This option will result in "TBISUSR.JCLCRS.DATA1" because the periods (.) are correctly placed to separate the symbolic parameters.

Option C) &GROUP.&DIV..&SUBJ.CRS.&TYPE.&NMBR. This option will result in "TBIS.USR.JCLCRS..DATA.1." because there are extra periods (.) between the symbolic parameters.

Option D) &GROUP.&DIV..&SUBJ.CRS..&TYPE.&NMBR. This option will result in "TBIS.USR.JCLCRS.DATA.1." because there are extra periods (.) between the symbolic parameters.

Therefore, the correct answers are B and C because they will result in the desired output of "TBISUSR.JCLCRS.DATA1".

• Thanks
• Wrong explanation