Number and Letter Coding Decoding

In the given code, each letter is assigned a unique digit: C=4, H=5, A=1, R=6, O=9, L=3, M=2, E=7. Applying this code to ALLOCHRE gives A=1, L=3, L=3, O=9, C=4, H=5, R=6, E=7, which is 13394567.

Each letter in DICTIONARY corresponds to a digit representing its position: D=1, I=2, C=3, T=4, O=5, N=6, A=7, R=8, Y=9. For ORDINARY: O=5, R=8, D=1, I=2, N=6, A=7, R=8, Y=9, giving 58126789.

From RAIN=8$%6: R=8, A=$, I=%, N=6. From MORE=7#8@: M=7, O=#, R=8, E=@. For REMAIN: R=8, E=@, M=7, A=$, I=%, N=6, giving 8@7$%6.

DECIDE=453945 gives: D=4, E=9, C=5, I=3. For 8978: 8=H, 9=I, 7=G, 8=H, spelling HIGH.

NOIDA=39658 gives: N=3, O=9, I=6, D=5, A=8. For INDIA: I=6, N=3, D=5, I=6, A=8, giving 63568.

Pattern: n² + 1. For n=2: 2²+1=5. For n=4: 4²+1=17≈18 (approximation). For n=6: 6²+1=37≈39. Following the pattern n²+1 exactly for n=10: 10²+1=101. However, the options suggest a different pattern: n×(n+1)/2 + n, or perhaps n² + n/2 for odd n. Let me reconsider: 2×2.5=5, 4×4.5=18, 6×6.5=39, 10×10.5=105. The pattern is n×(n+0.5).

Using the given mapping: 1=L, 7=F, 3=M, 8=E, 4=B, 6=K. So 173846 becomes L-F-M-E-B-K = LFMEBK.

Using the mapping: 4=B, 3=M, 0=P, 6=K, 7=F, 5=X. So 430675 becomes B-M-P-K-F-X = BMPKFX.

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

M is the 13^th letter of the English alphabet and Y is the 25^th letter. Based on this analogy, for BEEF we must have 2^nd, 5^th and 6^th letters. Hence, 2556.

266352; one is reduced and one is added alternately.

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

Using the mapping: 9=J, 0=P, 1=L, 2=D, 7=F, 3=M. So 901273 becomes J-P-L-D-F-M = JPLDFM.

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

From the codes for LOW, BOW and SOWS, we find that the group of digits 68 is common in all, which obviously stands for OW. In the code for SOWS, we find 68 which obviously stands for OW leaving the digit 3, which should naturally stand for S. In the code for BOWLS, we must have 68 for OW, 3 for S, and 4 and 7 respectively for L and B, which we find in answer choice (2).

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

The letters of the alphabet are allotted a numerical value. This analogical coding scheme can easily be correlated to reach the correct answer.

48703 (every letter of the alphabet is allotted an analogical coding with numerical value)