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Oxidation state of the central atom in A and B are _______ and _______ respectively.
A + H2O → C + H2O2 + O2
B + H2O → C
2B → D + 2K (At 670K)
K is pottasium
AnswerClick to flip back
A
+ 1, + 1
💡 Explanation:
A and B are KO2 and K2O respectively. As KO2 is a superoxide, oxidation number of K in it is +1, and in K2O the oxidation number is +1.