To answer this question, let's analyze the given SQL command:
SELECT name FROM employee WHERE name LIKE '_a%';
The LIKE keyword is used for pattern matching in SQL queries. In this case, it is used with the pattern '_a%'.
Let's break down the pattern:
_ (underscore): This represents a single character.a: This represents the character 'a'.% (percent sign): This represents any sequence of characters (including zero characters).
So, the pattern '_a%' means that we are looking for names with:
- Any single character as the first character.
- The second character as 'a'.
- Any sequence of characters (including zero characters) after the second character.
Now, let's go through each option to determine which names would be displayed:
Option A) Names starting with "a" - This option is incorrect. The pattern '_a%' does not specify that the names should start with "a". It only specifies that the second character should be "a".
Option B) Names with "a" as the second character - This option is correct. The pattern '_a%' matches names where the second character is "a". Therefore, this option correctly identifies the names that would be displayed.
Option C) Last character as "a" - This option is incorrect. The pattern '_a%' does not specify anything about the last character. It only specifies the second character as "a".
Option D) Names with at least two "a" at the start - This option is incorrect. The pattern '_a%' does not specify that there should be at least two "a" at the start. It only specifies the second character as "a".
Therefore, the correct answer is B) Names with "a" as the second character. This option correctly identifies the names that would be displayed based on the given SQL command.
