Multiple choice general knowledge math & puzzles

The age of the father 3 years ago was 7 times the age of his son. At present the father's age is 5 times that of his son. What are the present ages of the father and the son?

  1. 40 & 8

  2. 50 & 10

  3. 45 & 9

  4. 35 & 7
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the father's age be F and son's age be S. 3 years ago: F-3 = 7(S-3), so F = 7S - 18. Present: F = 5S. Equating: 5S = 7S - 18, giving 2S = 18, so S = 9. Then F = 5×9 = 45. Checking: 3 years ago, father was 42 and son was 6, and 42 = 7×6. Option C (45 & 9) is correct.

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